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- Question
What is the probabiltiy of getting a mutliple of 2 or 5 when an unbiased cubic die is thrown?
Options- A. 1/3
- B. 1/2
- C. 2/3
- D. 1/6
- Correct Answer
- 2/3
ExplanationTotal numbers in die=6
P(multiple of 2)=1/2
P(multiple of 5)=1/6
P(multiple of 2 or 5)=2/3
- 1. In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Options- A. 21/46
- B. 1/5
- C. 3/25
- D. 1/50 Discuss
- 2. A six-sided die with faces numbered 1 through 6 is rolled three times. What is the probability that the face with the number 6 on it will not face upward on all the three rolls?
Options- A. 215/216
- B. 1/216
- C. 215/256
- D. 1/52 Discuss
- 3. Find the probability that one ball is white when two balls are drawn at random from a basket that contains 9 red, 7 white and 4 black balls.
Options- A. 18/95
- B. 18/190
- C. 1/2
- D. 91/190 Discuss
- 4. One card is drawn from deck of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the ball drawn is red.
Options- A. 1/3
- B. 1/2
- C. 1/4
- D. 1/6 Discuss
- 5. Find the probability of selecting exactly 2 children when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.
Options- A. 9/29
- B. 10/21
- C. 12/21
- D. 14/19 Discuss
- 6. What is the probability that it is either a heart card or diamond card, when a card is drawn from a well shuffled standard pack of 52 playing cards?
Options- A. 1
- B. 1/2
- C. 3/4
- D. 1/3 Discuss
- 7. From well shuffled standard pack of 52 playing cards,one card is drawn. What is the probability that it is either a red card or black card?
Options- A. 1/2
- B. 3/4
- C. 1
- D. 1/3 Discuss
- 8. Find the probability that it is either white or red ball when,one ball is drawn at random in a bag that contains 3 black,4 white and 5 red balls
Options- A. 0.5
- B. 0.75
- C. 0.25
- D. 0.8 Discuss
- 9. The odds favouring the event of a person hitting a target are 3 to 5. The odds against the event of another person hitting the target are 3 to 2. If each of them fire once at the target, find the probability that both of them hit the target.
Options- A. 1/20
- B. 4/20
- C. 1/20
- D. 3/20 Discuss
- 10. Find the probability of selecting 2 woman when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.
Options- A. 1/5
- B. 1/7
- C. 1/6
- D. 1/9 Discuss
Probability problems
Search Results
Correct Answer: 21/46
Explanation:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S) = Number ways of selecting 3 students out of 25
= = 2300.
n(E)= = 1050.
P(E) = n(E)/n(s) = 1050/2300 = 21/46
Correct Answer: 215/216
Explanation:
Probability of getting 6 at the top once =1/6
Probability of getting 6 at the top three times =1/6 x 1/6 x 1/6 =216
Probability of no getting 6 at he top any time = 1 - 1/216 = 215/216
Correct Answer: 91/190
Explanation:
Total number of elementary events = ways =190
There are 7 white balls out of which one white can be drawn in 7 ways and one ball from remaining 13 balls can be drawn in ways.
So,favourable events =
Therfore,required probability = ( )/ =91/90
Correct Answer: 1/2
Explanation:
Total number of elementary events = 52
There are 26 red cards,out of which one red card can be drawn in ways =26.
So,required probability = 26/52 = 1/2
Correct Answer: 10/21
Explanation:
4 persons can be selected from 9 in ways =126
Fvaourable events = =60
So,required probability = 60/126 = 10/21
Correct Answer: 1/2
Explanation:
P(heart cards)=13/52
P(diamond cards)=13/52
P(heart or diamond)=13/52+13/52=1/2
Correct Answer: 1
Explanation:
P(red cards)=26/52
P(black cards)=26/52
P(red or black cards)=26/52+26/52=1
Correct Answer: 0.75
Explanation:
P(red ball) = 5/12
P(white ball) = 4/12
P(red or white ball) = 5/12 + 4/12 = 3/4 = 0.75
Correct Answer: 3/20
Explanation:
Let A be the event of first person hitting the target,
Let B be the event of Second person hitting a target.
Since both events are independent and both will hit the target so,
Correct Answer: 1/6
Explanation:
Out of 9 persons,4 can be choosen in ways =126.
Favourable events for given condition = = 21.
So,required probability = 21/126 =1/6.
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