Discussion
Home ‣ Aptitude ‣ Probability Comments
- Question
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?
Options- A. 2/3
- B. 1/2
- C. 7/8
- D. 4/5
- Correct Answer
- 1/2
ExplanationMultiples of 3 below 20 are 3, 6, 9, 12, 15, 18
Multiples of 5 below 20 are 5, 10, 15, 20
Required number of possibilities = 10
Total number of possibilities = 20
Required probability = 10/20 = 1/2. - 1. The probabilities that A and B will tell the truth are 2 / 3 and 4 / 5 respectively . What is the probability that they agree with each other ?
Options- A. 3/5
- B. 1/3
- C. 2/5
- D. 3/4 Discuss
- 2. One card is drawn from a pack of 52 cards,each of the 52 cards being equally likely to be drawn.Find the probability that the ball drawn is an ace :
Options- A. 1/13
- B. 1/12
- C. 1/14
- D. 1/15 Discuss
- 3. An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?
Options- A. 1/12
- B. 1/9
- C. 3/4
- D. 1/2 Discuss
- 4. A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Options- A. 2/13
- B. 1/13
- C. 1/26
- D. 1/52 Discuss
- 5. There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ?
Options- A. 1/10
- B. 1/9
- C. 1
- D. 0 Discuss
- 6. Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails
Options- A. 2
- B. 7/8
- C. 5/8
- D. 1/2 Discuss
- 7. A number is selected from the numbers 1,2,3,4.......25.The probability for it to be divisible by 4 or 7 is:
Options- A. 3/25
- B. 9/25
- C. 1/25
- D. None of these Discuss
- 8. Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.
Options- A. 2/7
- B. 3/7
- C. 4/7
- D. 3/7 Discuss
- 9. Two unbiased coin are tossed. What is the probability of getting atmost one head?
Options- A. 1/2
- B. 3/2
- C. 1/6
- D. 3/4 Discuss
- 10. You toss a coin AND roll a die. What is the probability of getting a tail and a 4 on the die?
Options- A. 1/2
- B. 1/12
- C. 2/3
- D. 3/4 Discuss
Probability problems
Search Results
Correct Answer: 3/5
Explanation:
Let A be the event of A will tell truth. B be the event of B tell truth
When both agree then they say true or they say false together, that is
Also these events will be mutually exclusive :
Correct Answer: 1/13
Explanation:
Total number of events=52
Number of aces =4
So,required probability = 4/52 =1/13
Correct Answer: 1/2
Explanation:
Total numbers in a die=6
P(mutliple of 3) = 2/6 = 1/3
P(multiple of 4) = 1/6
P(multiple of 3 or 4) = 1/3 + 1/6 = 1/2
Correct Answer: 1/26
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) =n(E)/n(S)=2/52=1/26.
Correct Answer: 0
Explanation:
As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address
P(E) = favorable outcomes /total outcomes
Here favorable outcomes are '0'.
So probability is '0'.
Correct Answer: 1/2
Explanation:
S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT }
=> n(S) = 8
E = { HHH, HHT, HTH, THH }
=> n(E) = 4
P(E) = 4/8 = 1/2
Correct Answer: 9/25
Explanation:
Total numbers = 25
Numbers divisible by 4 or 7 are 4, 7, 8, 12, 14, 16, 20, 21, 24 = 9
The probability (divisible by 4 or 7) = 9/25
Correct Answer: 2/7
Explanation:
Total number of persons = 9
Out of 9 persons 4 persons can be selected in ways =126
1 man,1 woman and 2 children can be selected in
ways =36
So,required probability = 36/126 =2/7
Correct Answer: 3/4
Explanation:
Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4
Correct Answer: 1/12
Explanation:
Probability of getting a tail when a single coin is tossed =12
Probability of getting 4 when a die is thrown =16
Required probability =(12)×(16)
= 1/12
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.