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- Question
Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
Options- A. 16/19
- B. 1
- C. 3/2
- D. 17/20
- Correct Answer
- 17/20
Explanationn(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(E U P) = 10/20 + 8/20 - 1/20 = 17/20 - 1. A card is drawn from a pack of 52 cards. The probability of getting a queen of the club or a king of the heart is?
Options- A. 1/26
- B. 1/13
- C. 2/13
- D. 1/52 Discuss
- 2. In a simultaneous throw of two dice, what is the probability of getting a total of 7 ?
Options- A. 1/6
- B. 1/4
- C. 1/20
- D. 3/4 Discuss
- 3. Out of sixty students, there are 14 who are taking Economics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class ?
Options- A. 8/15
- B. 7/15
- C. 1/15
- D. 4/15 Discuss
- 4. In a box, there are four marbles of white color and five marbles of black color. Two marbles are chosen randomly. What is the probability that both are of the same color?
Options- A. 2/9
- B. 5/9
- C. 4/9
- D. 0 Discuss
- 5. Three dice are thrown together.Find the probability of getting a total of atleast 6.
Options- A. 103/216
- B. 103/108
- C. 103/36
- D. 36/103 Discuss
- 6. A brother and a sister appear for an interview against two vacant posts in an office. The probability of the brother?s selection is 1/5 and that of the sister?s selection is 1/3. What is the probability that only one of them is selected?
Options- A. 1/5
- B. 3/4
- C. 2/5
- D. 3/5 Discuss
- 7. A bag contains 7 green and 5 black balls. Three balls are drawn one after the other. The probability of all three balls being green, if the balls drawn are not replaced will be:
Options- A. 123/897
- B. 23/67
- C. 7/44
- D. 12/45 Discuss
- 8. One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red.
Options- A. 2/3
- B. 1/2
- C. 1/52
- D. 13/51 Discuss
- 9. A bag contains 8 red and 4 green balls. Find the probability that two balls are red and one ball is green when three balls are drawn at random.
Options- A. 56/99
- B. 112/495
- C. 78/495
- D. None of these Discuss
- 10. If P(A)=4/9;then the odd against the event A is:
Options- A. 4:9
- B. 4:5
- C. 5:4
- D. 4:14 Discuss
Probability problems
Search Results
Correct Answer: 1/26
Explanation:
Here in this pack of cards, n(S) = 52
Let E = event of getting a queen of the club or a king of the heart
Then, n(E) = 2
P(E) = n(E)/n(S) = 2/52 = 1/26
Correct Answer: 1/6
Correct Answer: 7/15
Explanation:
Given total students in the class = 60
Students who are taking Economics = 24 and
Students who are taking Calculus = 32
Students who are taking both subjects = 60-(24 + 32) = 60 - 56 = 4
Students who are taking calculus only = 32 - 4 = 28
probability that a randomly chosen student from this group is taking only the Calculus class = 28/60 = 7/15.
Correct Answer: 4/9
Explanation:
Number of white marbles = 4
Number of Black marbles = 5
Total number of marbles = 9
Number of ways, two marbles picked randomly = 9C2
Now, the required probability of picked marbles are to be of same color = 4C2/9C2 + 5C2/9C2
= 1/6 + 5/18
= 4/9.
Correct Answer: 103/108
Explanation:
Total number of events=6 x 6 x 6=216
Let A be the event of getting a total of atleast 6 and B denoted event of getting a total of less than 6 i.e.,3,4,5.
So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)}
Favourable number of cases=10
Therefore,P(B)=10/216
=> P(A) = 1 - P(B)
= 1 - (10/216) = 103/108
Correct Answer: 2/5
Explanation:
Probability that only one of them is selected = (prob. that brother is selected) × (prob. that sister is not selected) + (Prob. that brother is not selected) × (Prob. that sister is selected)
= =
Correct Answer: 7/44
Explanation:
Here, n(E) =
And, n(S) =
P(S) =
= 7/44
Correct Answer: 1/2
Explanation:
We know that:
When one card is drawn from a pack of 52 cards
The numbers of possible outcomes n(s) = 52
We know that there are 26 red cards in the pack of 52 cards
? The numbers of favorable outcomes n(E) = 26
Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S)
? required probability = 26/52 = 1/2.
Correct Answer: 112/495
Explanation:
Correct Answer: 5:4
Explanation:
Here,P(A)=4/9=p/(p+q)
P(odd against event A)=q/p=5/4
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