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- Question
In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7.
Options- A. 1/2
- B. 5/12
- C. 7/15
- D. 3/12
- Correct Answer
- 5/12
ExplanationHere n(S) = (6 x 6) = 36
Let E = event of getting a total more than 7
= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}Therefore,P(E) = n(E)/n(S) = 15/36 = 5/12.
- 1. Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4?
Options- A. 3/7
- B. 7/11
- C. 5/9
- D. 6/13 Discuss
- 2. What is the probability that a number is divisible by 4?
Options- A. 2
- B. 1/2
- C. 1/4
- D. 1 Discuss
- 3. The probability that z lies between 0 and 3.01
Options- A. 0.4987
- B. 0.5
- C. 0.9987
- D. 0.1217 Discuss
- 4. Four dice are thrown simultaneously. Find the probability that all of them show the same face.
Options- A. 1/216
- B. 1/36
- C. 2/216
- D. 4/216 Discuss
- 5. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Options- A. 1/3
- B. 3/5
- C. 8/21
- D. 7/21 Discuss
- 6. A number X is chosen at random from the numbers -3, -2, -1, 0, 1, 2, 3. What is the probability that |X|<2
Options- A. 3/7
- B. 3/4
- C. 4/5
- D. 5/7 Discuss
- 7. A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Options- A. 10/21
- B. 11/21
- C. 1/2
- D. 2/7 Discuss
- 8. An unbiased die is tossed.Find the probability of getting a multiple of 3.
Options- A. 1/3
- B. 1/2
- C. 3/4
- D. 3/2 Discuss
- 9. In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.
Options- A. 16
- B. 12
- C. 10
- D. 14 Discuss
- 10. There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
Options- A. 1/2
- B. 3/4
- C. 4/7
- D. 3/8 Discuss
Probability problems
Search Results
Correct Answer: 5/9
Explanation:
Here n(S) = 6 x 6 = 36
E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)}
=> n(E)=20
Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.
Correct Answer: 1/2
Explanation:
Probability is Number of favourable outcomes by total outcomes
Total comes = 2 (Divisible or not)
Favourable = 1 (Divisible)
Hence, probability = 1/2.
Correct Answer: 0.4987
Explanation:
Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.
Correct Answer: 1/216
Explanation:
The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=
n(S) =
Let X be the event that all dice show the same face.
X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}
n(X) = 6
Hence required probability = =
Correct Answer: 1/3
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green
= event that the ball drawn is blue.
n(E) = 7.
P(E) = n(E)/n(S) = 7/21 = 1/3.
Correct Answer: 3/7
Explanation:
X can take 7 values.
To get |X|+2) take X={?1,0,1}
=> P(|X|<2) = Favourable CasesTotal Cases = 3/7
Correct Answer: 10/21
Explanation:
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7 = = 21
Let E = Event of drawing 2 balls, none of which is blue.
n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls = = 10
Therefore, P(E) = n(E)/n(S) = 10/ 21.
Correct Answer: 1/3
Explanation:
Here S = {1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
Then, E = {3,6}
P(E) = n(E)/n(S) = 2/6 = 1/3
Correct Answer: 12
Explanation:
Total balls = 40
Red balls = 18
Let green balls are x
Then, (18/40) × (
Correct Answer: 3/8
Explanation:
Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.
Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.
Required probability =24/64 = 3/8
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