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- Question
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Options- A. 3/4
- B. 3/8
- C. 5/16
- D. 2/7
- Correct Answer
- 3/4
ExplanationIn a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
Then, E= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3,4),(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
n(E) = 27.
P(E) = n(E)/n(S) = 27/36 = 3/4.
- 1. A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.
Options- A. 5/12
- B. 7/12
- C. 3/14
- D. 1/12 Discuss
- 2. The probabilities that a student will receive an A, B, C or D grade are 0.4, 0.3 , 0.2 and 0.1 respectively. Find the probability that a student will receive Atleast B grade.
Options- A. 0.21
- B. 0.3
- C. 0.7
- D. None of these Discuss
- 3. Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :
Options- A. 2/9
- B. 1/9
- C. 8/9
- D. 7/9 Discuss
- 4. A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?
Options- A. 13/42
- B. 17/42
- C. 5/42
- D. 3/14 Discuss
- 5. There are 26 balls marked with alphabetical order A to Z. What is the probability of selecting vowels listed balls?
Options- A. 1
- B. 21/26
- C. 5/26
- D. 5 Discuss
- 6. What is the probability of getting a sum 9 from two throws of a dice?
Options- A. 1/2
- B. 3/4
- C. 1/9
- D. 2/9 Discuss
- 7. In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear.
Options- A. 7/15
- B. 5/18
- C. 13/18
- D. 3/16 Discuss
- 8. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Options- A. 1/3
- B. 3/5
- C. 8/21
- D. 7/21 Discuss
- 9. Four dice are thrown simultaneously. Find the probability that all of them show the same face.
Options- A. 1/216
- B. 1/36
- C. 2/216
- D. 4/216 Discuss
- 10. The probability that z lies between 0 and 3.01
Options- A. 0.4987
- B. 0.5
- C. 0.9987
- D. 0.1217 Discuss
Probability problems
Search Results
Correct Answer: 5/12
Explanation:
Total number of elementary events =
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is
So,required probability = / = 5/12.
Correct Answer: 0.7
Explanation:
P(atleast B) = P( B or A) = P(B) + P(A) = (0.3) + (0.4) = 0.7
Correct Answer: 1/9
Explanation:
One person can select one house out of 3= ways =3.
Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.
Therefore, probability that all thre apply for the same house is 1/9
Correct Answer: 17/42
Explanation:
3 letters can be choosen out of 9 letters in ways.
More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in ways
Hence,required probability = = 17/42
Correct Answer: 5/26
Explanation:
We know that,
Total number of balls n(S) = 26
Number of vowels n(E) = 5
Hence, required probability = n(E)/n(S) = 5/26.
Correct Answer: 1/9
Explanation:
In two throws of a die, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =n(E)/n(S)=4/36=1/9.
Correct Answer: 5/18
Explanation:
n(S) = 36
A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}
B = { (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) }
Required probability =
=
= =
Correct Answer: 1/3
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green
= event that the ball drawn is blue.
n(E) = 7.
P(E) = n(E)/n(S) = 7/21 = 1/3.
Correct Answer: 1/216
Explanation:
The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=
n(S) =
Let X be the event that all dice show the same face.
X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}
n(X) = 6
Hence required probability = =
Correct Answer: 0.4987
Explanation:
Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987.
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