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- Question
A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is :
Options- A. 35/96
- B. 19/90
- C. 19/96
- D. None of these
- Correct Answer
- 19/90
ExplanationHere N and C are not common and same letters can be A, I, S, T. Therefore
Probability of choosing A = = 1/45
Probability of choosing I = = 1/45
Probability of choosing S = = 1/10
Probability of choosing T = = 1/15
Hence, Required probability =
- 1. Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6.
Options- A. 7/18
- B. 14/35
- C. 8/18
- D. 7/35 Discuss
- 2. A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
Options- A. 2/91
- B. 1/22
- C. 3/22
- D. 2/77 Discuss
- 3. What is the probability of getting 53 Mondays in a leap year?
Options- A. 1/7
- B. 3/7
- C. 2/7
- D. 1 Discuss
- 4. Two dice are tossed. The probability that the total score is a prime number is:
Options- A. 5/12
- B. 1/6
- C. 1/2
- D. 7/9 Discuss
- 5. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
Options- A. 1/2
- B. 3/5
- C. 9/20
- D. 8/15 Discuss
- 6. In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Options- A. 21/46
- B. 1/5
- C. 3/25
- D. 1/50 Discuss
- 7. A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?
Options- A. 136/345
- B. 17/87
- C. 316/435
- D. 158/435 Discuss
- 8. Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
Options- A. 3/20
- B. 29/34
- C. 47/100
- D. 13/102 Discuss
- 9. A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Options- A. 3/7
- B. 4/7
- C. 1/8
- D. 3/4 Discuss
- 10. Three unbiased coins are tossed.What is the probability of getting at least 2 heads?
Options- A. 1/4
- B. 1/2
- C. 3/4
- D. 1/3 Discuss
Probability problems
Search Results
Correct Answer: 7/18
Explanation:
Clearly, n(S) = 6 x 6 = 36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.
Then,E = {(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
n(E) = 14.
Hence, P(E) = n(E)/n(S) = 14/36 = 7/18
Correct Answer: 2/91
Explanation:
Let S be the sample space.
Then, n(S) = number of ways of drawing 3 balls out of 15 = = = 455.
Let E = event of getting all the 3 red balls.
n(E) = = = 10.
=> P(E) = n(E)/n(S) = 10/455 = 2/91.
Correct Answer: 2/7
Explanation:
1 year = 365 days . A leap year has 366 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364days
366 ? 364 = 2 days
In a leap year there will be 52 Sundays and 2 days will be left.
These 2 days can be:
1. Sunday, Monday
2. Monday, Tuesday
3. Tuesday, Wednesday
4. Wednesday, Thursday
5. Thursday, Friday
6. Friday, Saturday
7. Saturday, Sunday
Of these total 7 outcomes, the favourable outcomes are 2.
Hence the probability of getting 53 days = 2/7
Correct Answer: 5/12
Explanation:
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4,3),(5, 2), (5, 6), (6, 1), (6, 5) }
n(E) = 15.
P(E) = n(E)/n(S) = 15/36 = 5/12.
Correct Answer: 9/20
Explanation:
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = n(E)/n(S) = 9/20.
Correct Answer: 21/46
Correct Answer: 316/435
Explanation:
Let A be the event of getting two oranges and
B be the event of getting two non-defective fruits.
and be the event of getting two non-defective oranges
=
Correct Answer: 13/102
Explanation:
Let S be the sample space.
Then, n(S) = =(52 x 51)/(2 x 1) = 1326.
Let E = event of getting 1 spade and 1 heart.
n(E)= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = = 169.
P(E) = n(E)/n(S) = 169/1326 = 13/102.
Correct Answer: 4/7
Explanation:
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
P (drawing a white ball) = 8 /14 = 4/7.
Correct Answer: 1/2
Explanation:
Here S= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}.
Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.
P(E) = n(E) / n(S)
= 4/8= 1/2
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