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- Question
A cistern has one inlet, L and one inlet, M. L takes 5 hours to fill the empty tank, when M is not open and M takes 8 hours to empty the full tank, if the tank is two fifth full, how much time will it take to fill the tank completely when both L and M are opened simultaneously? (in hours)
Options- A. 5 hours
- B. 3 hours
- C. 6 hours
- D. 8 hours
- Correct Answer
- 8 hours
ExplanationIf the tank is 2/5th full, then remaining empty tank will be = 1-2/5=3/5thL and M can fill the empty tank in = (5*8)/(8-5)=40/3 hoursThen 3/5 th tank fill in =40/3 * 3/5= 8 hours
- 1. A water tank is 2/5 th full. Inlet A can fill the tank in 12 minutes while an outlet pipe B can empty it in 6minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
Options- A. It fills in 4.8 min
- B. It empties in 4.8 min
- C. It fills in 5.6 min
- D. It empties in 5.6 min Discuss
- 2. 18 buckets of water fill a tank when the capacity of each bucket is 8 litres. How many buckets will be needed to fill the same tank, if the capacity of the bucket is 12 litres?
Options- A. 12
- B. 13.5
- C. 24
- D. Data insufficient Discuss
- 3. Pipes A and B can fill a cistern in 15 hours together. But ifthese pipes operate separately A takes 40 hours less than Bto fill the tank. In how many hours the pipe A will fill thecistern working alone?
Options- A. 60
- B. 20
- C. 40
- D. 15 Discuss
- 4. Three pipe P, Q and R can fill a tank in 12 minutes, 18 minutesand 24 minutes respectively. The pipe R is closed 12 minutesbefore the tank is filled. In what time the tank is full?
Options- A. 8 (5/13) hrs
- B. 8 (4/13) hrs
- C. 7 (4/13) hrs
- D. 8 (6/13) hrs Discuss
- 5. A tank is filled in eight hours by three pipes K, L and M. Pipe K is twice as fast as pipe L, and L is twice as fast as M. How much time will pipe L alone take to fill the tank ?
Options- A. 32 hrs
- B. 24 hrs
- C. 28 hrs
- D. 26 hrs Discuss
- 6. An electric pump can fill a tank in 2 hours. Because of a leak in the tank, it was taking 21?2 hours to fill the tank. The leak can drain all the water off the tank in how many hours?
Options- A. 9
- B. 10
- C. 10.5
- D. 11.5 Discuss
- 7. Two pipes, when working one at a time, can fill a cistern in 3 hhrs and 4 hrs, resp while a third pipe can drain the cistern empty in 8 hrs. All the three pipes were opened together when the cistern was 1/12 full. How long did it take for the cistern to be completely full?
Options- A. 2 hrs
- B. 1 hr 45 min
- C. 2 hr 10 min
- D. 2 hr 11 min Discuss
- 8. A swimming pool is filled in 10 hours by three tankers A, B and C. The tanker C is twice as fast as B and B is twice as fast as A. How much time will tanker A alone take to fill the swimming pool?
Options- A. 90 hours
- B. 40 hours
- C. 70 hours
- D. 80 hours Discuss
- 9. Two taps X and Y can fill a tank in 15 hours and 20 hours respectively. If the two taps are opened at 2 p.m., then at what time (in p.m.) should the tap X be closed to completely fill the tank at exactly 2 a.m.?
Options- A. 8
- B. 7
- C. 9
- D. 10 Discuss
- 10. A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same colour.
Options- A. 1/2
- B. 7/15
- C. 8/15
- D. 1/9 Discuss
Pipes and Cistern problems
Search Results
Correct Answer: It empties in 4.8 min
Correct Answer: 12
Explanation:
Capacity of tank = (8 X 18) = 144 litres
If the capacity of each bucket = 12 litres
Then, Nunber of buckets needed = 144 / 12 = 12 buckets
Correct Answer: 20
Explanation:
Let A takes x hours, then B = (x+40) hours
1/x + 1/x+40 = 1/15
x = 20
Correct Answer: 8 (4/13) hrs
Correct Answer: 28 hrs
Explanation:
1/K + 1/L + 1/M = 1/8 (Given)
Also given that K = 2L and L = 2M
=> 1/2L + 1/L + 2/L = 1/8
=> (1 + 2 + 4)/2L = 1/8
=> 2L/7 = 8
=> L = 28 hours.
Correct Answer: 10
Correct Answer: 2 hrs
Correct Answer: 70 hours
Correct Answer: 8
Correct Answer: 7/15
Explanation:
Let S be the sample space
Then n(S) = no of ways of drawing 2 balls out of (6+4) = 10 = =45
Let E = event of getting both balls of same colour
Then,n(E) = no of ways (2 balls out of six) or (2 balls out of 4)
= = = 15+6 = 21
Therefore, P(E) = n(E)/n(S) = 21/45 = 7/15
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