Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
Let the required length be x meters
More men, More length built (Direct proportion)
Less days, Less length built (Direct Proportion)
=> (20 x 6 x X)=(35 x 3 x 56)
=> x = 49
Hence, the required length is 49 m.
when interest is reckoned using compound interest, interest being compounded annually. The difference in the simple interest and compound interest for two years is on account of the interest paid on the first year's interest Hence 12% of simple interest = 90 => simple interest =90/0.12 =750.
As the simple interest for a year = 750 @ 12% p.a., the principal =750/0.12 = Rs.6250.
If the principal is 6250, then the amount outstanding at the end of 3 years = 6250 + 3(simple interest on 6250) + 3 (interest on simple interest) + 1 (interest on interest on interest) = 6250 +3(750) + 3(90) + 1(10.80) = 8780.80.
Area of a square with side a = a² sq unts
Area of a triangle with base a = (1/2) * a * h sq.unts
a² =1/2 *a *h
=> h = 2a
altitude of the triangle is 2a
Given
Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.
Perimeter of a square p=4s ,where s=length of its side
=> p=4(14)=56 feets
Area of a square A = s x s
=> A=196
The perimeter is 56 feet, and the area is 196 square feet.
Area of square = 40 x 40
= 1600 sq.cm
Given that the areas of Square and Rectangle are equal
=> Area of rectangle = 1600 Sq.cm
We know that, Area of rectangle = L x B
Given L = 64 cm
Breadth of rectangle = 1600/64 = 25 cm
Perimeter of the rectangle = 2(L + B) = 2(64+25) = 178 cm.
Given numbers are 1.08 , 0.36 and 0.90
H.C.F of 108, 36 and 90 is 18 [ G.C.D is nothing but H.C.F]
Therefore, H.C.F of given numbers = 0.18
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