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- Question
Pipe K fills a tank in 30 minutes. Pipe L can fill the same tank 5 times as fast as pipe K. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow ?
Options- A. 3 minutes
- B. 2 minutes
- C. 4 minutes
- D. 5 minutes
- Correct Answer
- 5 minutes
ExplanationLet the total capacity of tank be 90 liters.
Capacity of tank filled in 1 minute by K = 3 liters.
Capacity of tank filled in 1 minute by L = 15 liters.
Therefore, capacity of the tank filled by both K and L in 1 minute = 18 liters.
Hence, time taken by both the pipes to overflow the tank = 90/18 = 5 minutes. - 1. Two filling taps P and Q together can fill a tank with rate of 40 lit/min and 60 lit/min respectively in 8 min. If a waste tap can empty the filled tank in 32 min, then what is the rate of waste tap ?
Options- A. 34 lit/min
- B. 25 lit/min
- C. 22 lit/min
- D. 18 lit/min Discuss
- 2. A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold ?
Options- A. 360 lit
- B. 480 lit
- C. 320 lit
- D. 420 lit Discuss
- 3. Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ?
Options- A. 24.315 minutes
- B. 26.166 minutes
- C. 22.154 minutes
- D. 24 minutes Discuss
- 4. A water tank in a village is normally filled in 8 hours but takes 2 hours longer to fill because of a leak in its bottom. If the tank is full, in how many hrs will the leak empty it ?
Options- A. 34 hrs
- B. 36 hrs
- C. 38 hrs
- D. 40 hrs Discuss
- 5. One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
Options- A. 6 min
- B. 8 min
- C. 12 min
- D. 10 min Discuss
- 6. A Tank is normally filled in 9 hours but takes four hours longer to fill because of a leak in its bottom. If the tank is full, the leak will empty it in ?
Options- A. 32.5 hrs
- B. 29.25 hrs
- C. 30.30 hrs
- D. 31 hrs Discuss
- 7. A water tank has holes. The 1st hole alone empties the tank in 9 min and 2nd hole alone empties the tank in 6 min. If water leaks out at a constant rate, how many min does it take if both the holes together empty the tank?
Options- A. 3 3/5
- B. 3/5
- C. 3 1/5
- D. 3 2/5 Discuss
- 8. Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank ?
Options- A. 15 min 20 sec.
- B. 16 min 40 sec.
- C. 13 min 10 sec.
- D. 14 min 40 sec. Discuss
- 9. Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern ?
Options- A. 85 min
- B. 95 min
- C. 105 min
- D. 100 min Discuss
- 10. In what time would a cistern be filled by three pipes which diameters are 2 cm, 3 cm and 4 cm running together, when the largest alone can fill it is 58 minutes? The amount of water flowing in each pipe is proportional to the square of its diameter.
Options- A. 26 min
- B. 32 min
- C. 36 min
- D. 42 min Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 25 lit/min
Explanation:
Given that the waste tap can empty the filled tank in 32 min.
Now, the rate at which the waste tap can empty the tank = (40 + 60)8/32 = 100/4 = 25 lit/min.
Correct Answer: 480 lit
Explanation:
1/k - 1/20 = -1/24
k = 120
120 x 4 = 480
Therefore, the capacity of the cistern is 480 liters.
Correct Answer: 26.166 minutes
Explanation:
Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120
For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120
So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120
So remaining tank = 13/120
Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.
So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes
Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.
Correct Answer: 40 hrs
Explanation:
The time taken by the leak to empty the tank =
Therefore, the leak empties the tank in 40 hours.
Correct Answer: 12 min
Explanation:
Let pipe A takes p min to fill
Then,
pipe B takes 3p min to fill
=> 3p - p = 32
=> p = 16 min => 3p = 48 min
Required, both pipes to fill = (48 x 16)/(48 + 16) min = 12 min.
Correct Answer: 29.25 hrs
Explanation:
Let the leak will empty the tank in x hrs
Then, 1/9 - 1/x = 1/13
x = 29.25 hrs
Correct Answer: 3 3/5
Correct Answer: 14 min 40 sec.
Explanation:
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 - 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 : k
k = (8/15 )x 1 x 20 = 10( 2/3) min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.
Correct Answer: 100 min
Explanation:
Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
Correct Answer: 32 min
Explanation:
Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm
From the given data,
Amount of water from three pipes is 4 units, 9 units and 16 units.
Let the capacity of cistern be 'p' units.
? p/58 = 16
? p = 928 units.
In 1 minute, quantity to be filled by 3 pipes = 29 units
? Total time required = 928/29 = 32 minutes.
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