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- Question
The ratio of efficiencies of two filling pipes is 4 : 5. There is a third emptying pipe which efficiency is two third of the average efficiency of first two filling pipes can empty a filled tank in 36 minutes. In how much time both the filling pipes can fill the tank when it is empty?
Options- A. 16 min
- B. 12 min
- C. 14 min
- D. 20 min
- Correct Answer
- 12 min
ExplanationLet the efficiencies of filling pipes is 4p and 5p respectively.
Efficiency of pipe which empty the tank = 2/3 x 9p/2 = 3p
Total work = 3p x 36 = 108p
Time to fill the tank by both the pipes = 108p/9p = 12 min.
- 1. Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes ?
Options- A. 21 min
- B. 24 min
- C. 20 min
- D. 22 min Discuss
- 2. The capacity of a tank is 2400 m3 . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.
Options- A. 46 cub.m/min
- B. 44 cub.m/min
- C. 48 cub.m/min
- D. 50 cub.m/min Discuss
- 3. Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank?
Options- A. 48min
- B. 72min
- C. 24min
- D. None of these Discuss
- 4. Pipe A is an inlet pipe that can fill an empty cistern in 69 hours. Pipe B can drain the filled cistern in 46hours. When the cistern was filled the two pipes are opened one at a time for an hour each, starting withPipe B. how long will it take for the cistern to be empty?
Options- A. 11 days 10 hours
- B. 11 days 7 hours
- C. 11 days 12 hours
- D. 1 days 13 hours Discuss
- 5. A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half ?
Options- A. 31 min
- B. 29 min
- C. 28 min
- D. 30 min Discuss
- 6. A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely ?
Options- A. 4 hrs 15 min
- B. 3 hrs 24 min
- C. 4 hrs 51 min
- D. 3 hrs 45 min Discuss
- 7. One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
Options- A. 6 min
- B. 8 min
- C. 12 min
- D. 10 min Discuss
- 8. A water tank in a village is normally filled in 8 hours but takes 2 hours longer to fill because of a leak in its bottom. If the tank is full, in how many hrs will the leak empty it ?
Options- A. 34 hrs
- B. 36 hrs
- C. 38 hrs
- D. 40 hrs Discuss
- 9. Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ?
Options- A. 24.315 minutes
- B. 26.166 minutes
- C. 22.154 minutes
- D. 24 minutes Discuss
- 10. A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold ?
Options- A. 360 lit
- B. 480 lit
- C. 320 lit
- D. 420 lit Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 21 min
Explanation:
Let the pipe B be closed after 'K' minutes.
30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16
=> K = 14/16 x 24 = 21 min.
Correct Answer: 50 cub.m/min
Explanation:
Let filling capacity of the pump be 'F'
Then, the filling capacity of the pump will be (F + 10)
From the given data,
Correct Answer: 24min
Explanation:
Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,
part filled by tap X in 1 minute = 1/30
part filled by tap Y in 1 minute = 1/40
Tap Z can empty the tank in 60 minutes. Therefore,
part emptied by tap Z in 1 minute = 1/60
Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24
i.e., the tank can be filled in 24 minutes.
Correct Answer: 11 days 7 hours
Correct Answer: 30 min
Explanation:
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 min.
Correct Answer: 3 hrs 45 min
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 x 1/6 = 2/3
Remaining part = 1 - 1/2 = 1/2
2/3 : 1/2 :: 1 : p
p = 1/2 x 1 x 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.
Correct Answer: 12 min
Explanation:
Let pipe A takes p min to fill
Then,
pipe B takes 3p min to fill
=> 3p - p = 32
=> p = 16 min => 3p = 48 min
Required, both pipes to fill = (48 x 16)/(48 + 16) min = 12 min.
Correct Answer: 40 hrs
Explanation:
The time taken by the leak to empty the tank =
Therefore, the leak empties the tank in 40 hours.
Correct Answer: 26.166 minutes
Explanation:
Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120
For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120
So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120
So remaining tank = 13/120
Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.
So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes
Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.
Correct Answer: 480 lit
Explanation:
1/k - 1/20 = -1/24
k = 120
120 x 4 = 480
Therefore, the capacity of the cistern is 480 liters.
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