Required number of ways =
In the word 'CORPORATION', we treat the vowels OOAIO as one letter.
Thus, we have CRPRTN (OOAIO).
This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.
Number of ways arranging these letters =7!/2!= 2520.
Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged in 3!/5!= 20 ways.
Required number of ways = (2520 x 20) = 50400.
A team of 6 members has to be selected from the 10 players. This can be done in 10C6 or 210 ways.
Now, the captain can be selected from these 6 players in 6 ways.
Therefore, total ways the selection can be made is 210×6= 1260
When R and W are the first and last letters of all the words then we can arrange them in 5!ways. Similarly When W and R are the first and last letters of the words then the remaining letters can be arrange in 5! ways.
Thus the total number of permutations = 2 x 5! = 2 x 120 = 240
The first, the seventh, the ninth and the tenth letters of the word RECREATIONAL are R, T, O and N respectively. Meaningful word from these letters is only TORN. The third letter of the word is ?R?.
The given digits are 1, 2, 3, 5, 7, 9
Number of even numbers = ?P? = 60.
Three digit number will have unit?s, ten?s and hundred?s place.
Out of 5 given digits any one can take the unit?s place.
This can be done in 5 ways. ... (i)
After filling the unit?s place, any of the four remaining digits can take the ten?s place.
This can be done in 4 ways. ... (ii)
After filling in ten?s place, hundred?s place can be filled from any of the three remaining digits.
This can be done in 3 ways. ... (iii)
So,by counting principle, the number of 3 digit numbers = 5x 4 x 3 = 60
P(4,3)= = 24
6P4 = 6! / (6-4)! = 360
= 15504
Since it does not matter what order the committee members are chosen in, the combination formula is used.
Committees are always a combination unless the problem states that someone like a president has higher hierarchy over another person. If the committee is ordered, then it is a permutation.
C(17,7)= 19,448
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