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- Question
Find the total number of distinct vehicle numbers that can be formed using two letters followed by two numbers. Letters need to be distinct
Options- A. 65000
- B. 64000
- C. 72000
- D. 36000
- Correct Answer
- 65000
ExplanationOut of 26 alphabets two distinct letters can be chosen in ways. Coming to numbers part, there are 10 ways.(any number from 0 to 9 can be chosen) to choose the first digit and similarly another 10ways to choose the second digit. Hence there are totally 10X10 = 100 ways.
Combined with letters there are X 100 ways = 65000 ways to choose vehicle numbers.
- 1. The product of two consecutive odd number is 6723. What is the greater number?
Options- A. 89
- B. 85
- C. 91
- D. 83 Discuss
- 2. Average value of property of three persons A, B, C is ? 11111 crore. The property of C is as less as the property of A is greater than the average property of both C and A. The value of property of B is.
Options- A. 110 crore
- B. 11211 crore
- C. 11111 crore
- D. 21410 crore Discuss
- 3. The number of digits in the numeral for 2 64?
Options- A. 18 digit
- B. 19 digit
- C. 20 digit
- D. 21digit Discuss
- 4. 36800 - 9999 - 3333 - 66 =?
Options- A. 30200
- B. 27912
- C. 23402
- D. 24102 Discuss
- 5. An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
Options- A. 144°
- B. 150°
- C. 168°
- D. 180° Discuss
- 6. A train travels 100 meters at 70 km hour. A man is running at 10 km per hour in the same direction. What time the train will pass the man?
Options- A. 6 seconds
- B. 62/3 seconds
- C. 7 second
- D. 8 second Discuss
- 7. 8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of water is 16 : 65. How much wine did the cask hold originally?
Options- A. 18 litres
- B. 24 litres
- C. 32 litres
- D. 42 litres Discuss
- 8. What percent of 7.2 kg is 18 gms?
Options- A. .025%
- B. .25%
- C. 2.5%
- D. 25% Discuss
- 9. Find the cube root of 19683.
Options- A. 25
- B. 26
- C. 28
- D. 27 Discuss
- 10. A cost of cultivating a square field at a rate of ? 135 per hectare is ? 1215. The cost of putting a fence around it at the rate of 75 paise per meter wouldbe
Options- A. ? 360
- B. ? 810
- C. ? 900
- D. ? 1800 Discuss
More questions
Correct Answer: 83
Explanation:
Let two consecutive odd number be (A + 1) and (A + 3).
According to the question.
(A + 1) (A + 3) = 6723
? A2 + 3A + A + 3 = 6723
? A2 + 4A + 3 - 6723 = 0
? A2 + 4A - 6720 = 0
? A2 + 84A - 80A - 6720 = 0
? A(A + 84) - 80 (A + 84) = 0
? (A - 80) (A + 84) = 0
? A = 80, (A = ? - 84)
Hence, the greater number = 80 + 3 = 83
Correct Answer: 11111 crore
Explanation:
( A + B + C ) / 3 = 11111 ....(i)
Also, ( A+C ) / 2 = 11111 ....(ii)
From Eqs. (i) & (ii), we get
B = ? 11111 crore
Correct Answer: 20 digit
Explanation:
? x = 264
? log x = log 264
? log x = 64 log 2
= 64 x .3010 = 19.264
? No.of digits = 19 + 1 = 20
Correct Answer: 23402
Explanation:
36800 - 9999 - 3333 - 66 = 36800 - ( 9999 - 3333 - 66)
= 36800 - 13398
= 23402
Correct Answer: 180°
Explanation:
| Angle traced by the hour hand in 6 hours = | ❨ | 360 | x 6 | ❩ | ° | = 180°. |
| 12 |
Correct Answer: 6 seconds
Explanation:
Relative speed of the train
= (70 - 10)
= 60 km/hr
= (60 x 5/18)
= 50/3) m/sec.
? Time taken by the train to pass the man
= (100 x 3/50) = 6 sec.
Correct Answer: 24 litres
Explanation:
| Then, quantity of wine left in cask after 4 operations = | [ | x | ❨ | 1 - | 8 | ❩ | 4 | ] litres. |
| x |
| ∴ | ❨ | x(1 - (8/x))4 | ❩ | = | 16 |
| x | 81 |
| ⟹ | ❨ | 1 - | 8 | ❩ | 4 | = | ❨ | 2 | ❩ | 4 |
| x | 3 |
| ⟹ | ❨ | x - 8 | ❩ | = | 2 |
| x | 3 |
⟹ 3x - 24 = 2x
⟹ x = 24.
Correct Answer: .25%
Explanation:
7.2 kg = 7.2 x 1000000 gm = 7200000 gms
Required percentage = (18/7200000) x 100 % = 0.25%
Correct Answer: 27
Explanation:
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
Correct Answer: ? 900
Explanation:
Area of the field =1215/135 = 9 hec
= 90000 m2 [1 hec =10000 m2]
? Side of the field = ?90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m
Now, cost of putting a fence around field = (1200 x 75)/100 = ? 900
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