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  • Question
  • In how many ways can 5 letters be posted in 4 letter boxes?


  • Options
  • A. 512
  • B. 1024
  • C. 625
  • D. 20

  • Correct Answer
  • 1024 

    Explanation

    First letter can be posted in 4 letter boxes in 4 ways. Similarly second letter can be posted in 4 letter boxes in 4 ways and so on.

    Hence all the 5 letters can be posted in = 4 x 4 x 4 x 4 x 4 = 1024


  • Permutation and Combination problems


    Search Results


    • 1. 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

    • Options
    • A. 2880
    • B. 1440
    • C. 720
    • D. 2020
    • Discuss
    • 2. In how many ways the letters of the word NUMERICAL can be arranged so that the consonants always occupy the even places ?

    • Options
    • A. 5!
    • B. 6!
    • C. 4!
    • D. Can't determine
    • Discuss
    • 3. In how many different ways can the letters of the word 'THERAPY' be arranged so that the vowels never come together?

    • Options
    • A. 1440
    • B. 720
    • C. 2250
    • D. 3600
    • Discuss
    • 4. If repetition of the digits is allowed, then the number of even natural numbers having three digits is :

    • Options
    • A. 550
    • B. 450
    • C. 500
    • D. 540
    • Discuss
    • 5. Compute the sum of 4 digit numbers which can be formed with the four digits 1,3,5,7, if each digit is used only once in each arrangement.

    • Options
    • A. 105555
    • B. 106665
    • C. 106656
    • D. 108333
    • Discuss
    • 6. Using numbers from 0 to 9 the number of 5 digit telephone numbers that can be formed is

    • Options
    • A. 1,00,000
    • B. 59,049
    • C. 3439
    • D. 6561
    • Discuss
    • 7. If you have 6 New Year greeting cards and you want to send them to 4 of your friends, in how many ways can this be done?

    • Options
    • A. 720
    • B. 360
    • C. 240
    • D. 740
    • Discuss
    • 8. A coach must choose five starters from a team of 12 players. How many different ways can the coach choose the starters ?

    • Options
    • A. 569
    • B. 729
    • C. 625
    • D. 769
    • Discuss
    • 9. If a+b+c =21 what is the total number of positive integral solutions?

    • Options
    • A. 109
    • B. 190
    • C. 901
    • D. 910
    • Discuss
    • 10. If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ?

    • Options
    • A. 51/1221
    • B. 42/221
    • C. 1/221
    • D. 52/1245
    • Discuss


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