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  • Question
  • A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ? A) 11/91 B) 4/11 C) 1/11 D) 90/91


  • Options
  • A. Option A
  • B. Option B
  • C. Option C
  • D. Option D

  • Correct Answer
  • Option D 

    Explanation

    Let S be the sample space. Then,
    n(s) = number of ways of drawing 4 pearls out of 14


    = C 4 14  ways =  14 × 13 × 12 × 11 4 × 3 × 2 × 1 = 1001


    Let E be the event of drawing 4 pearls of the same colour.
    Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5)

       ? C 1 5 +   C 4 4 +   C 1 5  = 5+1+5 =11

     P(E) =  n ( E ) n ( S ) = 11 1001 = 1 91   

     

     Required probability =  1 - 1 91 = 90 91

  • Tags: CAT, Bank Exams, Bank PO, Bank Clerk

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