Discussion
Home ‣ Aptitude ‣ Percentage Comments
- Question
90% of X = 40% of Y and Y = a% of X. What is the value of a?
Options- A. 225
- B. 125
- C. 2.25
- D. 1.25
- Correct Answer
- 225
- 1. There are two buckets, smaller bucket can hold only 3/5th of the water as compared to the larger bucket. If 6,000 buckets of larger capacity are needed to fill a pond. Then how many smaller capacity buckets are needed to fill the same pond?
Options- A. 8000
- B. 10000
- C. 12000
- D. 15000 Discuss
- 2. Price of petrol increased from Rs 60/liter to Rs 75/liter. How much should the consumption of petrol be reduced (in %) so as to increase expenditure by only 10%?
Options- A. 12
- B. 20
- C. 15
- D. 18 Discuss
- 3. 0.09% of 25% of 1200 is equal to____________.
Options- A. 0.27
- B. 2.7
- C. 27
- D. 270 Discuss
- 4. If on an item there is 12% discount on the marked price of Rs 10,000 but the item is sold at Rs 8,360 only then what additional discount (in %) did the customer get?
Options- A. 6
- B. 7
- C. 5
- D. 8 Discuss
- 5. If a website is selling smartphone at Rs 18,000 which is marked at Rs 25,000, then what is the discount (in %) at which the smartphone is being sold?
Options- A. 25
- B. 22
- C. 28
- D. 20 Discuss
- 6. A student multiplied a number by 6/13 instead of 13/6. What is the percentage error in the calculation?
Options- A. 369.44 percent
- B. 39.35 percent
- C. 184.72 percent
- D. 78.7 percent Discuss
- 7. An engineering student has to secure 36% marks to pass. He gets 53 and fails by 37 marks. Find the maximum marks.
Options- A. 275 marks
- B. 250 marks
- C. 300 marks
- D. 325 marks Discuss
- 8. An engineering student has to secure 25% marks to pass. He gets 47 and fails by 43 marks. What are the maximum marks of the examination?
Options- A. 385 marks
- B. 410 marks
- C. 360 marks
- D. 435 marks Discuss
- 9. If the selling price of an item is Rs 1150 after getting a discount of 8%, what is its marked price?
Options- A. Rs 1250
- B. Rs 1242
- C. Rs 1058
- D. Rs 1064 Discuss
- 10. Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
Options- A. 25200
- B. 52000
- C. 120
- D. 24400 Discuss
Percentage problems
Search Results
Correct Answer: 10000
Correct Answer: 12
Correct Answer: 0.27
Correct Answer: 5
Correct Answer: 28
Correct Answer: 78.7 percent
Correct Answer: 250 marks
Correct Answer: 360 marks
Correct Answer: Rs 1250
Correct Answer: 25200
Explanation:
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = ( * )
= 210.
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
Number of ways of arranging 5 letters among themselves = 5! = 120
Required number of ways = (210 x 120) = 25200.
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.