In a hoel, 60% had vegetarian lunch while 30% had non-vegetaian lunch and 15% ha

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Question
In a hoel, 60% had vegetarian lunch while 30% had non-vegetaian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ?
Options
A. 24
B. 30
C. 36
D. 42

Correct Answer

24

Explanation

n (A) = (60/100 * 96) = 288/5, n (B) = (30/100 * 96) = 144/5, n (A ? B) = (15/100 * 96) = 72/5.

n(A ? B) = n (A) + n (B) - n (A ? B) = 72.

So, people who had either or both types of lunch = 72.

Hence, people who had neither type of lunch = (96 - 72)= 24.

5. If a retailer offers a discount of 28% on the marked price of his goods and thus ends up selling at cost price, what was the % mark up?
Options
A. 18.25 percent
B. 22 percent
C. 38.88 percent
D. 28 percent

9. A trader sold a cycle at a loss of 10%. If the selling price had been increased by Rs. 200, there would have been a gain of 6%. The cost price of the cycle is
Options
A. Rs.1200
B. Rs.1205
C. Rs.1250
D. Rs.1275

10. A?s salary is 50% more than B?s. How much percent is B?s salary less than A?s?
Options
A. 24.5%
B. 29.5%
C. 31.3%
D. 33.3%

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