K = 100 L = 130
130------ 30
100------- ? => 23 1/13 %
20 x 55 x 66 = L x 65 x 70
Here L = 72,600/4550 = 15.95 =~ 16
Reduction is 20-16 = 4
which is 20% reduction.
Value of Maruti Van, V1 = Rs. 1,96,000
Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 years
Let V2 is the value after depreciation.
V2 =
V2 = 196000(6/7)(6/7)
V2 = (196000x36)/49 = Rs. 1,44,000.
circumference of A =
= 8 => so r =
volume =
=
circumference of B =
= 10 => so r =
volume =
=
so ratio of capacities = 160/200 = 0.8
so capacity of A will be 80% of the capacity of B.
Let 'x' be the amount he had in the bank.
=> 20/100(25/100(30/100(x))) = 750
x = 750 x 8000/120 = Rs. 50000
As these three strategies P, Q and R are independent so these will cut cost one after the other.
If initial cost is Rs 100, then
20% cost is cut after initializing strategy P, then cost will remain 80% = 80
further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56
further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4
Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.
12% of 70,000
=> 12 x 70,000/100
=> 8400
Hence, 12% of 70,000 = 8,400
75% of 450 + ? % of 560 = 600
Hence, in the given question ? = 46.875
From the given data,
20% of 120
20 x 120/100
= 4 x 6
= 24
Hence, 20% of 120 = 24.
6% of 350000
Hence, 6% of 3,50,000 = 21,000.
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