Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.
Given SD makes 1/4 th of the total fleet.
=> 8 = 1/4 (21 + x)
=> 32 = 21 + x
=> x = 11
Therefore, the company has 11 small cars.
From the given data,
(60 - 45)% = 12.5 + 4
15% = 16.5
=> 100% = ?
100% = 16.5 x 100/15 = 110
Hence, P = 45% of 110 = 45x110/100 = 49.5
Q = 50% of 110 = 55
R = 60% of 110 = 60 x 110/100 = 66
M = 12.5 + 49.5 = 62 or 66 - 4 = 62
Hence, no statement is required to answer.
If earlier he is getting Rs. 1 per hr and working for 1 hr, income = Rs. 1
Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs
Then income for 0.66667 hrs = Rs. 0.8889.
If payment per hr is increased by 33.33 % and working hours dereased by 33.33%, then 11.11 % decrease in income.
Given monday population = 3000
Per day 20% increase in population.
Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600
Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320
Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184
So that day is Thursday.
As these three strategies P, Q and R are independent so these will cut cost one after the other.
If initial cost is Rs 100, then
20% cost is cut after initializing strategy P, then cost will remain 80% = 80
further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56
further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4
Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.
Let 'x' be the amount he had in the bank.
=> 20/100(25/100(30/100(x))) = 750
x = 750 x 8000/120 = Rs. 50000
circumference of A =
= 8 => so r =
volume =
=
circumference of B =
= 10 => so r =
volume =
=
so ratio of capacities = 160/200 = 0.8
so capacity of A will be 80% of the capacity of B.
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