63.5% of 8924.2 +? % of 5324.4 = 6827.5862
=> 63.5% of 8925 + ? % of 5325 = 6830
=> 6830 ~= 5320 + ?(5325)/100
=> ? ~= 22
Let the total amount he had with = Rs. p
From the given data,
p - 38460 - 24468 = 28p/100
p - 28p/100 = 24468 + 38460
72p/100 = 62928
72p = 62928 x 100
p = 62928 x 100/72
p = 87400
Hence, the total amount he had = p = Rs. 87400.
Given 21% of 500 + 31% of 1100 - 30% of 790 = ?
? = 21 x 5 + 31 x 11 - 3 x 79
? = 105 + 341 - 237
? = 446 - 237
? = 209.
In that 35% are Hindu, 30% are Sikh, 15% are Muslims
=> 35 + 30 + 15 = 80%
Remaining Boys = 100% - 80% = 20% of 1500
=> 20 x 1500/100 = 300 boys are Christians.
Let 'P' be the original population at the beginning
P x (95/100) x (85/100) = 3553
P = 4400.
Imension of the duster is assumed as 5x5x7 cm3
Volume of the duster below the water layer
= volume of water increased
= ?xrxrxh = 3.14×52×2.14 ? 168 cm3
Total volume of the duster = 5×5×7 = 175 cm3
Percentage of the duster part below the layer = 168×100/175 = 96%
Percentage of the duster part above the layer = 4%
Given
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