(100-x)% of 88% of 8400 = 6896
=>
=> x = 6.709%
Suppose total earnings = Rs. 10000
10% saving = 10000 x (10/100) = Rs. 1000
This year 5% more income than prev year = Rs. 10500
12% saving = 10500 x (12/100) = Rs. 1260
Percentage of amount saved = (1260/1000) x 100 = 126%
Let K = Kalyan's monthly salary
N = Nandu's monthly salary
S = Sarnesh's monthly salary.
Then from given data,
12% of K = 16% of N
S = N/2 => N = 2S
K = 16/12 x N = 16/12 x 2S
= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000
Since Area of Rectangle = side1 x side2
Therefore, error% in area
=
%
= [20 - 10 + ( -10 x 20)/100]% or 8%
i.e. 8% excess.
Reduction in consumption
=
X 100%
=
X 100%
= 20%
Number of runs made by running = 180 - (11 x 4 + 8 x 6)
= 180 - (92)
= 88
Now, we need to calculate 88 is what percent of 180.
= 48.888%.
Imension of the duster is assumed as 5x5x7 cm3
Volume of the duster below the water layer
= volume of water increased
= ?xrxrxh = 3.14×52×2.14 ? 168 cm3
Total volume of the duster = 5×5×7 = 175 cm3
Percentage of the duster part below the layer = 168×100/175 = 96%
Percentage of the duster part above the layer = 4%
Let 'P' be the original population at the beginning
P x (95/100) x (85/100) = 3553
P = 4400.
In that 35% are Hindu, 30% are Sikh, 15% are Muslims
=> 35 + 30 + 15 = 80%
Remaining Boys = 100% - 80% = 20% of 1500
=> 20 x 1500/100 = 300 boys are Christians.
Given 21% of 500 + 31% of 1100 - 30% of 790 = ?
? = 21 x 5 + 31 x 11 - 3 x 79
? = 105 + 341 - 237
? = 446 - 237
? = 209.
Let the total amount he had with = Rs. p
From the given data,
p - 38460 - 24468 = 28p/100
p - 28p/100 = 24468 + 38460
72p/100 = 62928
72p = 62928 x 100
p = 62928 x 100/72
p = 87400
Hence, the total amount he had = p = Rs. 87400.
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