Reduction in consumption
=
X 100%
=
X 100%
= 20%
Number of runs made by running = 180 - (11 x 4 + 8 x 6)
= 180 - (92)
= 88
Now, we need to calculate 88 is what percent of 180.
= 48.888%.
Here 85 of 352 => 85 is what percent in 352
Let p% of 352 is 85
Percentage(%) is generally calculated in the total of 100.
=> p x 352/100 = 85
=> p = 8500/352 = 24.14%
Hence, 85 is 24.14% of 352.
Let his monthly salary be 'P'
20% on children's education =
50% on food and transport =
1000 on rent
=>
Therefore, his monthly salary = Rs. 10,000
There is no need to use the no of goats i.e (34,398). let initially thete be 1000 goats then
1000 -----> 1400 -----> 980 -----> 1274 ----->1146.6
Thus the % increase = (1146.6-1000)/100 x 100= 14.66%
Since Area of Rectangle = side1 x side2
Therefore, error% in area
=
%
= [20 - 10 + ( -10 x 20)/100]% or 8%
i.e. 8% excess.
Let K = Kalyan's monthly salary
N = Nandu's monthly salary
S = Sarnesh's monthly salary.
Then from given data,
12% of K = 16% of N
S = N/2 => N = 2S
K = 16/12 x N = 16/12 x 2S
= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000
Suppose total earnings = Rs. 10000
10% saving = 10000 x (10/100) = Rs. 1000
This year 5% more income than prev year = Rs. 10500
12% saving = 10500 x (12/100) = Rs. 1260
Percentage of amount saved = (1260/1000) x 100 = 126%
(100-x)% of 88% of 8400 = 6896
=>
=> x = 6.709%
Imension of the duster is assumed as 5x5x7 cm3
Volume of the duster below the water layer
= volume of water increased
= ?xrxrxh = 3.14×52×2.14 ? 168 cm3
Total volume of the duster = 5×5×7 = 175 cm3
Percentage of the duster part below the layer = 168×100/175 = 96%
Percentage of the duster part above the layer = 4%
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