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- Question
If the price of diesel increases by 25% and Karthik intends to spend only an additional 15% on diesel, by how much % will he reduce the quantity of diesel purchased ?
Options- A. 6.67 %
- B. 8 %
- C. 7.41 %
- D. 9 %
- Correct Answer
- 8 %
ExplanationLet the price of 1 litre of diesel be Rs.x and let Karthik initially buy 'y' litres of diesel.
Therefore, he would have spent Rs. xy on diesel.When the price of diesel increases by 25%, the new price per litre of diesel is 1.25x.
Karthik intends to increase the amount he spends on diesel by 15%.
i.e., he is willing to spend xy + 15% of xy = 1.15xyLet the new quantity of diesel that he can get be 'q'.
Then, 1.25x x q = 1.15xy
Or q = (1.15/1.25)y = 0.92y.As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier.
Or a reduction of 8%.
- 1. A sum ? 1440 is lent out in three parts in such a way that the interest on first part at 2% for 3 yr, second part at 3% for 4 yr and third part at 4% for 5 yr equal . Then, the difference between the largest and the smallest sum is?
Options- A. ? 400
- B. ? 560
- C. ? 460
- D. ? 200 Discuss
- 2. A man buys a music system valued at ? 8000. He pays ? 3500 at once and rest 18 months later, on which he is charged simple interest at the rate of 8% per annum . Find the total amount he pays for the music system?
Options- A. ? 9260
- B. ? 8540
- C. ? 8720
- D. ? 9410 Discuss
- 3. A man invests a certain sum of money at 6% per annum simple interest and another at 7% per annum simple interest. His income from interest after 2 yr was ? 792. Also, half of the first sum is equal to one-third of the second sum. The total sum invested was?
Options- A. ? 5800
- B. ?. 6200
- C. ? 6000
- D. ? 5900 Discuss
- 4. A borrowed ? 4800 from B at 9% per annum simple interest for 3 yr. He, then added some more money to the borrowed sum and lent it to C for the same period at 12% per annum simple interest. If A gains ? 720 in the whole transaction, how much money did he add from his side?
Options- A. ? 500
- B. ? 740
- C. ? 640
- D. ? 800 Discuss
- 5. A person closer his account in an investment scheme by withdrawing ? 10000. One year ago, he had withdraw ? 6000. Two years ago, he had withdrawn ? 5000. Three years ago, he had not withdrawn any money. How much money had he deposited approximately at the time of opening the account 4 yr ago, if the annual simple interest is 10%?
Options- A. ? 15600
- B. ? 16500
- C. ? 17280
- D. None of these Discuss
- 6. Mr. Pawan invests an amount of ? 242000 at the rate of 4% per annum for 6 yr to obtain a simple interest, later he invests the principal amount as well as the amount obtained as simple interest for another 4 yr at the same rate of interest. What amount of simple interest will be obtained at the end of the last 4 yr?
Options- A. ? 4800
- B. ? 4850.32
- C. ? 4801.28
- D. ? 4700 Discuss
- 7. Rajnish invested certain sum in three different schemes P, Q and R with the rates of interest 10% per annum, 12% per annum and 15% per annum, respectively. If the total interest accrued in 1 yr was ? 3200 and the amount invested in scheme R was 150% of the amount invested in scheme Q. what was the amount invested in scheme Q?
Options- A. ? 8000
- B. ? 9000
- C. ? 5000
- D. ? 3050 Discuss
- 8. The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. The sum is?
Options- A. Rs. 600
- B. Rs. 500
- C. Rs. 400
- D. Rs. 300 Discuss
- 9. If the compound interest on a certain sum for 2 years at 12.5% per annum is 170, the simple interest is?
Options- A. Rs. 150
- B. Rs. 152.50
- C. Rs. 160
- D. Rs. 162.50 Discuss
- 10. A sum amounts to Rs. 1352 in 2 years at 4% compound interest.The sum is?
Options- A. Rs. 1300
- B. Rs. 1250
- C. Rs. 1260
- D. Rs. 1200 Discuss
More questions
Correct Answer: ? 560
Explanation:
Let the first part be ? A.
second part be ? B
and third part be Rs C
According to the question.
(A x 2 x 3)/100 = (B x 3 x 4)/100 = (C x 4 x 5)/ 100
? 3A = 6B = 10C = k
? A = k/3, B = k/100 and C = k /10
Now, A + B + C = 1440
? k/3 + k/6 + k/10 = 1440 ? k = 2400
? so the difference = k/3 - k/10 = 7k/30 = 7/30 x 2400 = ? 560
Correct Answer: ? 8540
Explanation:
Cost of the music system = ? 8000
Money paid at once = ? 3500
Money left = (8000 - 3500) = ? 4500
Time = (18/12) = 3/2 yr and R = 8% per annum
SI = PTR/100 = (4500 x 3/2 x 8)/100 = ? 540
Money to be paid at the end = (4500 + 540) = ? 5040
? Cost of music system = (3500 + 5040) = ? 8540
Correct Answer: ? 6000
Explanation:
Let the sum be P and Q, respectively.
Then, (P x 6 x 2)/100 + (Q x 7 x 2)/100 = 792
? 6P + 7Q = 39600 ...(i)
Also P/2 = Q/3 ? 3P = 2Q ... (ii)
On solving Eqs . (i) and (ii), we get P = 2400 and Q = 3600
? Total sum = (2400 + 3600) = ? 6000
Correct Answer: ? 800
Explanation:
Let the money added be ? P, Then,
[(4800 + P) x 12 x 3]/100 - (4800 x 9 x 3)/100 = 720
? (4800 + P) x 36 - (4800 x 27) = 720 x 100
? (4800 + P) x 4 - (4800 x 3) = 8000
? 4800 + P - (1200 x 3 ) = 2000
? P + 1200 = 2000
? P = 800
So, money added is ? 800.
Correct Answer: None of these
Explanation:
Suppose the person had deposited ? P at the time of opening the account .
? After one year he had P + (P x 10 x 1)/100 = ? 11P/10
After two years, he had
11P/10 + (11P/10 x 10 x 1)/100 = ? 121P/100 ...(i)
After withdrawn ? 5000 from ? 121P/100, the balance
= ? (121P - 500000)/100
After 3 yr, he had
(121P - 500000)/100 + [(121P - 500000)/100 x 10 x 1]/100
= 11(121P - 500000)/100 ... (ii)
After withdrawn ? 6000 from amount (ii) the balance
= (1331P/1000 - 11500)
? After 4 yr, he had ? (1331P - 5500000)/1000 + 10% of ? (1331P - 5500000)/1000
= ? (11/10) x (1331P/1000 - 11500) ... (iii)
After withdrawn ? 10000 from amount (iii) the balance =0
? 11/10(1331P/1000 - 11500) - 10000 = 0
? P = ? 15470
Correct Answer: ? 4801.28
Explanation:
In the case I,
SI = (P x R x T) /100 = (24200 x 4 x 6) / 100 = ? 5808
? Amount = Principal + SI
SI = 24200 + 5808 = 30008
In the case II,
SI = (30008 x 4 x 4) / 100 = ? 4801.28
Correct Answer: ? 5000
Explanation:
Let a, b and c be the amount invested in schemes P, Q and R, respectively.
Then, according to the question,
[(a x 10 x 1)/100] + [(b x 12 x 1)/100] + [(c x 15 x 1)/100] = 3200
? 10a + 12b + 15x = 320000 .....(i)
Now, c = 240% of b = 12b/5 ....(ii)
and c = 150% of a = 3a/2
? a = 2c/3 = (2/3 x 12/5) b = 8b/5 .....(iii)
From Eqs. (i), (ii) and (iii), we get
16b + 12b + 36b = 320000
? 64b = 320000
? b = 5000
? Sum invested in scheme Q = ? 5000
Correct Answer: Rs. 600
Explanation:
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)2} - 100] = Rs. 41/4
? Difference between C.I and S.I = Rs. (41/4 - 10) = Re. 0.25
? 0.25 : 150 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Correct Answer: Rs. 160
Explanation:
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2 - p = 170
? p x (112.5/100) x (112.5/100) - p = 170
? P [ 12656.25 - 10000 ] = 170 x 10000
? p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
Correct Answer: Rs. 1250
Explanation:
Let the sum be P.
Then, 1352 = P(1 +4/100)2
? 1352 = P x 26/25 x 26/25
? P = (1352 x 25 x 25) / (26 x 26) = 1250
? Principal = Rs. 1250
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