Given 82.5% of 2360
Given
of 259.99 = ? % of 1247.9
24/5 x 260 = ? x 1248/100
? = 1248 x 100/1248
? = 100.
what is 70 of 50 means 70% of 50
Hence, 70 of 50 is 35.
Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of K and L be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 8720
32.5k = 32.5k/100k x 8720 = 2834
The number of valid votes polled in favour of L is 2834.
Let the amount collected be 'A'
Then, from the given conditions,
A x 110/100 x 90/100 = 7920
A x 0.99 = 7920
A = 7920/0.99
=> 8000
We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
=
=
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.
Therefore, the purchase price of the machine was Rs. 12,000.
Total engineers = 4800
Number of female engineers = 3/8 x 4800 = 1800
Then, number of male engineers = 4800 - 1800 = 3000
Now, required is female engineers is what percentage of the number of male engineers
=> 1800 is what % of 3000
=> p x 3000/100 = 1800
=> 30p = 1800
p = 60%
Hence, female engineers is 60 percentage of the number of male engineers.
From the given data in the question,
t = 4 years.
Let the number of students = 100
Number of students who failed in one or more subjects = 14 + 22 + 18 = 54%
The percentage of students who passed in both the subjects = 100 - 54 = 46%.
Ramesh : Rajesh =(50,000*36) : (75,000*30) =4 : 5.
Therefore, Rajesh's share=Rs.(27,000*5/9)= Rs.15,000.
Let the Original capital amount be Rs. P
Given after 2 years the amount is Rs. 10000
Rate of interest = 30%
According to the question,
Therefore, the capital amount P = Rs. 5917
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