We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
=
=
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.
Therefore, the purchase price of the machine was Rs. 12,000.
Here, x = 40 and y = 30;
Therefore second number
= [[
] x 100 ]% of first number
= [[
] x 100 ]% of first number
Second number = 92.8% of the first number.
Let the total quantity of gold be p kgs.
According to the question,
50% of p + 25% of p + 12.5% of p = 130900
87.5% of p = 130900
p = 130900 x 100/87.5 = 149600 kgs.
Therefore, the initial gold quantity that king has = p = 149600 kgs.
Given the price of a commodity is decreased by p = 20%
And its consumption is increased by q = 10%
Now, required increase or decrease in the expenditure on the commodity can be
p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%.
Hence, decrease in the expenditure = 12%
56% of 870 = 56x870/100 = 487.20
82% of 180 = 82x180/100 = 147.60
32% of 90 = 32x90/100
487.20 + 147.6 - 28.8 = ?
? = 634.8 - 28.8
? = 606.
Let 36 is p% of 80
=> p x 80/100 = 36
=> p = 36 x 10/8 = 45.
Let the amount collected be 'A'
Then, from the given conditions,
A x 110/100 x 90/100 = 7920
A x 0.99 = 7920
A = 7920/0.99
=> 8000
Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of K and L be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 8720
32.5k = 32.5k/100k x 8720 = 2834
The number of valid votes polled in favour of L is 2834.
what is 70 of 50 means 70% of 50
Hence, 70 of 50 is 35.
Given
of 259.99 = ? % of 1247.9
24/5 x 260 = ? x 1248/100
? = 1248 x 100/1248
? = 100.
Given 82.5% of 2360
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