56% of 870 = 56x870/100 = 487.20
82% of 180 = 82x180/100 = 147.60
32% of 90 = 32x90/100
487.20 + 147.6 - 28.8 = ?
? = 634.8 - 28.8
? = 606.
Let 36 is p% of 80
=> p x 80/100 = 36
=> p = 36 x 10/8 = 45.
The discount offered by showroom = 18%
Raghu purchased at Rs. 54540
Then,
The marked price is given by
54540 x 100/82
=~ Rs. 66,512
Let Veena's weight = 1 kg
Sana's weight = 2 kg
Sneha's weight = 1.4 kg
Rina's weight = 1.8 kg
Now,according to the given data in the question,
x = .
Let marks obtained by N = x
M's marks = 0.80x
L's marks = 1.25 (0.80x)
K's marks = (0.90) (1.25) (0.80x)
= 0.9x
But 0.9x = 360 ? x = 400
Percentage of Marks obtained by N
= 400 x 100/500 = 80%
Given the price of a commodity is decreased by p = 20%
And its consumption is increased by q = 10%
Now, required increase or decrease in the expenditure on the commodity can be
p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%.
Hence, decrease in the expenditure = 12%
Let the total quantity of gold be p kgs.
According to the question,
50% of p + 25% of p + 12.5% of p = 130900
87.5% of p = 130900
p = 130900 x 100/87.5 = 149600 kgs.
Therefore, the initial gold quantity that king has = p = 149600 kgs.
Here, x = 40 and y = 30;
Therefore second number
= [[
] x 100 ]% of first number
= [[
] x 100 ]% of first number
Second number = 92.8% of the first number.
We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
=
=
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.
Therefore, the purchase price of the machine was Rs. 12,000.
Let the amount collected be 'A'
Then, from the given conditions,
A x 110/100 x 90/100 = 7920
A x 0.99 = 7920
A = 7920/0.99
=> 8000
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