Let X = Time taken for each of Type B Problems(100 Problems)
And 2X = Time taken for each of Type A problems(50 problems)
Total time period = 3hrs = 3 x 60min = 180 minutes
100X + 50(2X) = 180
100X + 100X = 180
200X = 180 min
X = 180/200
X = 0.90 min
By convertiing into seconds,
X = 0.90 x 60 seconds
X = 54 sec
So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds
= 5400/60sec = 90 minutes.
Let the total applicants be 100
Then, 20% got 85 marks
i.e 20 x 85 = 1700
and 25% got 95 marks
i.e 25 x 95 = 2375
Now, the remaining applicants are 55 and let the average marks scored by them be x.
Therefore, 2375 + 1700 + 55x =
6000 - 4075 = 55x
55x=1925
x=35.
Let the total earnings be Rs.x
Then % of x + % of (x-12000) =2400
=> x=50,589.47
52.5% of 800 + 30.5% of 2800 = ? + 87.30
420 + 854 - 87.30 = ?
1274 - 87.30 = ?
? = 1186.70
Let Akhil's weight = p kg
=> Shreyon's weight = 2p kg
Nani's weight = 0.9 x 2p = 1.8p kg
=> Arun's weight = 1.4p kg
Required percentage =
= 77.8%
~= 78%
74.99% of 1299 + 8.98% of 1899 = ?
I II III
65 58 100
65 -------- 7
100 ------ ? => 10.769%
6.72/100 = 672/10000 = 42/625
1/2 as a percentage means
1/2 = 0.5 in decimal
Now, in percentage means 0.5 x 100% = 50%.
Total number of female members = 115
Let the number of males = x
Number of females = y
=> x + y = 115 ......(1)
According to the given data,
x + y(0.50) = 69 ......(2)
From (1) & (2), we get
0.5y = 46
=> y = 46 x 2 = 92
=> x = 115 - 92 = 23
Hence, required number of gentlemen in the family = x = 23.
Here it is asked that 3 is what percent of 5
Let 3 is K percent of 5.
=> K x 5/100 = 3
=> K = 300/5 = 60
Hence, 3 is 60% of 5.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.