Discussion
Home ‣ Aptitude ‣ Percentage Comments
- Question
In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ?
Options- A. 60
- B. 52
- C. 45
- D. 35
- Correct Answer
- 35
ExplanationLet the total applicants be 100
Then, 20% got 85 marks
i.e 20 x 85 = 1700
and 25% got 95 marks
i.e 25 x 95 = 2375
Now, the remaining applicants are 55 and let the average marks scored by them be x.
Therefore, 2375 + 1700 + 55x =
6000 - 4075 = 55x
55x=1925
x=35.
- 1. A sales boy is allowed 412 % discount on the total sales made by him plus a bonus of 14 % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?
Options- A. Rs.60,145.23
- B. Rs.54,285.54
- C. Rs.52,147.85
- D. Rs.50,589.47 Discuss
- 2. What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30
Options- A. 1096.30
- B. 1226.70
- C. 1124.20
- D. 1186.70 Discuss
- 3. Arun?s weight is 140% of Akhil?s weight. Nani?s weight is 90% of Shreyon?s weight. Shreyon?s weight is twice as much as Akhil?s. What percentage of Arun?s weight is Nani?s weight?
Options- A. 76%
- B. 77%
- C. 78%
- D. 79% Discuss
- 4. 74.99% of 1299 + 8.98% of 1899 = ?
Options- A. 1378
- B. 1301
- C. 1212
- D. 1197 Discuss
- 5. In order to maximize his gain, a shopping mall owner decides to reduce the price of electronics goods by 20% and as a result of this, the sales of electronics increase by 40%. If, as a result of these changes, he is able to increase his weekly collection by Rs. 1,05,000, find by what value did the gross collection increase per day?
Options- A. Rs. 14400
- B. Rs. 14600
- C. Rs. 14800
- D. Rs. 15000 Discuss
- 6. If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ?
Options- A. 75 min
- B. 82 min
- C. 90 min
- D. 101 min Discuss
- 7. Two numbers are 35% and 42% are less than a third number .How much percent is the second number less than the first ?
Options- A. 10.769 %
- B. 11.23 %
- C. 10.4 %
- D. 9.87 % Discuss
- 8. Express 6.72 % in ratio ?
Options- A. 65 : 124
- B. 42 : 625
- C. 21 : 125
- D. 37 : 442 Discuss
- 9. 1/2 as a percentage?
Options- A. 50%
- B. 5%
- C. 0.5%
- D. 0.05% Discuss
- 10. Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family?
Options- A. 23
- B. 92
- C. 48
- D. 52 Discuss
Percentage problems
Search Results
Correct Answer: Rs.50,589.47
Explanation:
Let the total earnings be Rs.x
Then % of x + % of (x-12000) =2400
=> x=50,589.47
Correct Answer: 1186.70
Explanation:
52.5% of 800 + 30.5% of 2800 = ? + 87.30
420 + 854 - 87.30 = ?
1274 - 87.30 = ?
? = 1186.70
Correct Answer: 78%
Explanation:
Let Akhil's weight = p kg
=> Shreyon's weight = 2p kg
Nani's weight = 0.9 x 2p = 1.8p kg
=> Arun's weight = 1.4p kg
Required percentage =
= 77.8%
~= 78%
Correct Answer: 1212
Explanation:
74.99% of 1299 + 8.98% of 1899 = ?
Correct Answer: 90 min
Explanation:
Let X = Time taken for each of Type B Problems(100 Problems)
And 2X = Time taken for each of Type A problems(50 problems)
Total time period = 3hrs = 3 x 60min = 180 minutes
100X + 50(2X) = 180
100X + 100X = 180
200X = 180 min
X = 180/200
X = 0.90 min
By convertiing into seconds,
X = 0.90 x 60 seconds
X = 54 sec
So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds
= 5400/60sec = 90 minutes.
Correct Answer: 10.769 %
Explanation:
I II III
65 58 100
65 -------- 7
100 ------ ? => 10.769%
Correct Answer: 42 : 625
Explanation:
6.72/100 = 672/10000 = 42/625
Correct Answer: 50%
Explanation:
1/2 as a percentage means
1/2 = 0.5 in decimal
Now, in percentage means 0.5 x 100% = 50%.
Correct Answer: 23
Explanation:
Total number of female members = 115
Let the number of males = x
Number of females = y
=> x + y = 115 ......(1)
According to the given data,
x + y(0.50) = 69 ......(2)
From (1) & (2), we get
0.5y = 46
=> y = 46 x 2 = 92
=> x = 115 - 92 = 23
Hence, required number of gentlemen in the family = x = 23.
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.