74.99% of 1299 + 8.98% of 1899 = ?
Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,
As we know:
Simple interest (S.I.) = PTR/100
(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200
= 10a + 12b + 15c = 320000 .........(1)
Now, c = 240% of b = 12b/5 .........(2)
And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)
From (1), (2) and (3), we have
16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000
? Sum invested in Scheme Y = Rs.5000.
From the given data,
let the amounts invested be 4p, 5p and 3p
Net profit = Total profit - Total loss
= 10x5p/100 + 25x3p/200 - 20x4p/100
= 0.875p - 0.8p
= 0.075p
Therefore, profit% = (Net profit/Total investment) x 100
= 0.075 x 100/12
= 0.0625%
Let the required number be 'p'
36 of what number is 18 implies 36% of p = 18
=> 36 x p/100 = 18
=> p = 1800/36
=> p = 50.
Hence, 36% of 50 is 18.
Let the total population be 'P'
P x (96/100) = 23040
P = 240 * 100
P = 24000.
Let Akhil's weight = p kg
=> Shreyon's weight = 2p kg
Nani's weight = 0.9 x 2p = 1.8p kg
=> Arun's weight = 1.4p kg
Required percentage =
= 77.8%
~= 78%
52.5% of 800 + 30.5% of 2800 = ? + 87.30
420 + 854 - 87.30 = ?
1274 - 87.30 = ?
? = 1186.70
Let the total earnings be Rs.x
Then % of x + % of (x-12000) =2400
=> x=50,589.47
Let the total applicants be 100
Then, 20% got 85 marks
i.e 20 x 85 = 1700
and 25% got 95 marks
i.e 25 x 95 = 2375
Now, the remaining applicants are 55 and let the average marks scored by them be x.
Therefore, 2375 + 1700 + 55x =
6000 - 4075 = 55x
55x=1925
x=35.
Let X = Time taken for each of Type B Problems(100 Problems)
And 2X = Time taken for each of Type A problems(50 problems)
Total time period = 3hrs = 3 x 60min = 180 minutes
100X + 50(2X) = 180
100X + 100X = 180
200X = 180 min
X = 180/200
X = 0.90 min
By convertiing into seconds,
X = 0.90 x 60 seconds
X = 54 sec
So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds
= 5400/60sec = 90 minutes.
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