Let C's salary be Rs. x
Then B's salary = 80x/100
=> A's salary = (50/100) * (80x/100) = 40x/100
But given total earnings in a month = 22000
=> x + 80x/100 + 40x/100 = 22000
=> x + 120x/100 = 22000
=> x = 10000
=> A's salary = 40 x 10000/100 = Rs. 4000
Let number of pages in a book = p
According to questions
p - [3p/7 + (2/5 x 4p/7)] = 36
= p - 23p/35 = 36
=> 12p = 36 × 35
p = 105
Let marks obtained by S = M
R's marks = 0.80M
Q's marks = 1.25 (0.80M)
P's marks = (0.90) (1.25) (0.80M)
= 0.9M
But 0.9M = 360
M = ?
M = 400
Hence % of marks obtained by S
= 400/500 x 100 = 80%.
Let number of boys = B
Number of girls = G
From the given data,
1B/3 + 1G/2 = 300
But given B/3 = 100
=> B = 300
G/2 = 300 - 100
G = 200 x 2
=> G = 400
Therefore, total number of students in the college = B + G = 700.
This can be solved as
80x900/100 + 256 x 4 x ? = 1331 - 99
720 + 1024 x ? = 1232
? = 1232 - 720/1024
? = 512/1024 = 0.5
? = 0.5
only (c) is correct since it is divisible by 4.
Let the original number of element be x then the new no.of elements will be
So K must be divisible by 4
Since, x = Kx5/4
The surface area of a cube = 6 = 6
New Surface area = 6 x 1.44
Therefore, %
Let N be the required number.
=>
=> N = 2664x2x7x5/9
=> N = 20720.
In the question it is asked for 5% of 1500
5 x 1500/100 = 15 x 5 = 75.
Hence, 5% of 1,500 is equal to 75.
From the given data,
20% of K = 32% of N
V = 4/5 N
Given Vipin's salary = 3.84 lpa = 3.84/12 = 32,000 per month
Now, N = 5/4 x 32000 = 40000
Now K = 32/20 x 40000 = 64000
Hence, karthik's monthly salary = Rs. 64000.
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