n (A) = 34, n (B) = 42, n (A ? B) = 20.
So, n (A U B) = n (A) + n(B) - n(A ?B) = 34 + 42 - 20 = 56.
Percentage failed in either or both the subjects = 56.
Hence, percentage passed = (100 - 66)% = 44%.
Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60
Required percentage = [(60/120)*100] % = 50%
From the given data,
P = 140
But it is given that,
40% of Q + Q = 140 = P
=> Q + [40Q/100] = 140
=> [100Q + 40Q]/100 = 140
=> 140Q = 140 x 100
=> Q = 100
Now,
3/25 of Q
= (3/25) x 100
= 3 x 4
= 12
Required 3/25 of Q = 12.
Given 56% of 225 + 20% of 150 = ? - 109
we know that a% of b = b% of a
Now,
225% of 56 + 20% of 150 = ? - 109
200% of 56 + 25% of 56 + 20% of 150 = ? - 109
112 + 14 + 30 = ? - 109
? = 112 + 14 + 30 + 109
? = 264
Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.
Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50
Total sales tax paid = 7% of Rs, 400 + 9% of Rs. 6400
=Rs. (7/100)*400 + (9/100)*6400 = Rs. (28 + 576) = Rs. 604.
Total cost of the items = Rs. (400 + 6400) = Rs. 6800.
Required percentage =(604/6800*100) % = %.
=>x = 174 => 87%
Let the original price of rice be Rs. x
Let rice a man can buy for Rs. 500 at rs. x/kg be = R kgs
From given data, for Rs. 500
x ---- R kgs
(x + 25x/100) ---- (R - 5) kgs
=> Rx = (R - 5)(x + 25x/100)
=> Rx = (R - 5)(125x/100)
=> 100Rx = 125Rx - 625x
=> R = 25
So at rate of Rs. x/kg, man get 25 kgs for Rs. 500
=> x = 500/25 = Rs. 20
30 + (.0825 x 30) + (15% x 30)
Now
=> 0.0825 x 30 = 2.475 -----(1)
=> 15% of 30 = 450/100 = 4.5 -----(2)
Hence, from (1) & (2)
30 + (.0825 x 30) + (15% x 30)
= 30 + 2.475 + 4.5
30 + (.0825 x 30) + (15% x 30) = 36.975.
Let the original price of the cycle be 100. After the first reduction the price will be 75.
This new price is then reduced by 20% = 0.8 x 75 = 60
60 represents a reduction of 40 percent on the original.
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