Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.
Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50
Let the total sale be Rs. x.
Then, 2.5%. of x = 12.50
=> (25/100 * 1/100 * x) = 125/10
=> x = 500.
From the given data,
When the price of rice is decreased by 10%, the value of Rs. 270 would become
270 x 100/90 = 300
Now, the value 270 becomes 300
And given, the girl could buy 1 kg extra for that value
Change in value = 300 - 270 = Rs. 30
Therefore, 1 kg extra rice she can get for Rs. 30
=> The original price of rice = Rs. 30/kg.
As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.
Let his present earnings be Rs. p
ATQ,
(125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000
p = Rs. 40,000.
Given 56% of 225 + 20% of 150 = ? - 109
we know that a% of b = b% of a
Now,
225% of 56 + 20% of 150 = ? - 109
200% of 56 + 25% of 56 + 20% of 150 = ? - 109
112 + 14 + 30 = ? - 109
? = 112 + 14 + 30 + 109
? = 264
From the given data,
P = 140
But it is given that,
40% of Q + Q = 140 = P
=> Q + [40Q/100] = 140
=> [100Q + 40Q]/100 = 140
=> 140Q = 140 x 100
=> Q = 100
Now,
3/25 of Q
= (3/25) x 100
= 3 x 4
= 12
Required 3/25 of Q = 12.
Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60
Required percentage = [(60/120)*100] % = 50%
n (A) = 34, n (B) = 42, n (A ? B) = 20.
So, n (A U B) = n (A) + n(B) - n(A ?B) = 34 + 42 - 20 = 56.
Percentage failed in either or both the subjects = 56.
Hence, percentage passed = (100 - 66)% = 44%.
Total sales tax paid = 7% of Rs, 400 + 9% of Rs. 6400
=Rs. (7/100)*400 + (9/100)*6400 = Rs. (28 + 576) = Rs. 604.
Total cost of the items = Rs. (400 + 6400) = Rs. 6800.
Required percentage =(604/6800*100) % = %.
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