Let the total sale be Rs. x.
Then, 2.5%. of x = 12.50
=> (25/100 * 1/100 * x) = 125/10
=> x = 500.
From the given data,
When the price of rice is decreased by 10%, the value of Rs. 270 would become
270 x 100/90 = 300
Now, the value 270 becomes 300
And given, the girl could buy 1 kg extra for that value
Change in value = 300 - 270 = Rs. 30
Therefore, 1 kg extra rice she can get for Rs. 30
=> The original price of rice = Rs. 30/kg.
As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.
Let his present earnings be Rs. p
ATQ,
(125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000
p = Rs. 40,000.
Here, x = 20 and y = - 20
Therefore, the net % change in value
=
%
=
% or - 4%
Since the sign is negative, there is a decrease in value by 4%.
Let the number be x. Then, x-(2/5)x = 510
=> 3x/5 =510
=>x =[510 * ( 5/3)] =850
10 % 0f 850 = 85.
Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50
Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.
Given 56% of 225 + 20% of 150 = ? - 109
we know that a% of b = b% of a
Now,
225% of 56 + 20% of 150 = ? - 109
200% of 56 + 25% of 56 + 20% of 150 = ? - 109
112 + 14 + 30 = ? - 109
? = 112 + 14 + 30 + 109
? = 264
From the given data,
P = 140
But it is given that,
40% of Q + Q = 140 = P
=> Q + [40Q/100] = 140
=> [100Q + 40Q]/100 = 140
=> 140Q = 140 x 100
=> Q = 100
Now,
3/25 of Q
= (3/25) x 100
= 3 x 4
= 12
Required 3/25 of Q = 12.
Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60
Required percentage = [(60/120)*100] % = 50%
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