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- Question
Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ?
Options- A. 60%
- B. 40%
- C. 50%
- D. 30%
- Correct Answer
- 40%
ExplanationLets say shyam sells at 100,
Since Ram sells 25% cheaper than Shyam,
Therefor Ram sells at less than 25% of100 or 75 rs.
Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or
125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.
Hence Brams Good is 40% cheaper than that of Shyam's good.
- 1. The diference of two numbers is 20% of the larger number, if the smaller number is 20, then the larger number is :
Options- A. 15
- B. 25
- C. 35
- D. 45 Discuss
- 2. In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ?
Options- A. 4000
- B. 8000
- C. 12000
- D. 16000 Discuss
- 3. In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was :
Options- A. 10 kg
- B. 15 kg
- C. 20 kg
- D. 25 kg Discuss
- 4. Of the 1000 inhabitants of a town, 60 % are males of whom 120 % are literate. If, of all the inhabitants, 25% are literate, then what percent of the females of the town are literate ?
Options- A. 32.5 %
- B. 43 %
- C. 46.6 %
- D. 53.2 % Discuss
- 5. If 15% of x = 20% of y, then x:y is ___?
Options- A. 4:3
- B. 5:4
- C. 4:5
- D. 3:4 Discuss
- 6. What percent decrease in salaries would exactly cancel out the 20 percent increase ?
Options- A. (16 + 2/3) %
- B. (15 + 2/3)%
- C. (14 +1/3)%
- D. (13 + 4/5)% Discuss
- 7. A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :
Options- A. 21.6 %
- B. 15.3 %
- C. 14.6 %
- D. 12.5 % Discuss
- 8. If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?
Options- A. 31/25
- B. 15/17
- C. 14/25
- D. 11/16 Discuss
- 9. The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :
Options- A. 60
- B. 70
- C. 80
- D. 90 Discuss
- 10. In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?
Options- A. 1060
- B. 960
- C. 1020
- D. 920 Discuss
Percentage problems
Search Results
Correct Answer: 25
Explanation:
Let the large number be x.
Then x - 20 = 20x/100
=> x - x/5 = 20 => x = 25.
Correct Answer: 8000
Explanation:
Let the number of candidates appeared from each state be x.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 80 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 80
=> total appeared candidates in State B = 80 x 100 = 8000
=> total appeared candidates in State A = total appeared candidates in State B = 8000
Correct Answer: 10 kg
Explanation:
Let the original quantity be x kg. Vanaspati ghee in x kg = (40x / 100 )kg = (2x / 5) kg.
Now, (2x/5)/(x + 10) = 20/100
=> 2x / (5x + 50) = 1/5
=> 5x = 50
=> x = 10.
Correct Answer: 32.5 %
Explanation:
Number of males = 60% of 1000 = 600. Number of females = (1000 - 600) = 400.
Number of literates = 25% of 1000 = 250.
Number of literate males = 20% of 600 = 120.
Number of literate females = (250 - 120) = 130.
Required pecentage = (130/400 * 100 ) % = 32.5 %.
Correct Answer: 4:3
Explanation:
Given 15% of x = 20% of y
=> 15x = 20y
=> x/y = 20/15
=> x : y = 4 : 3
Correct Answer: (16 + 2/3) %
Explanation:
Let the orginal salary = Rs. 100. New's salary = Rs.120.
Decrease on 120 = 20. Decrease on 100 = [(20/120)*100]% = (16 + 2/3) %.
Correct Answer: 21.6 %
Explanation:
Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.
25 paise coins removed = Rs. (600*12/100) = 72.
50 paise coins removed = Rs. (1200*24/100)= 288.
Money removed =Rs.(72*25/100+288*50/100) = Rs.162.
Required percentage = (162/750*100)% = 21.6 %.
Correct Answer: 15/17
Explanation:
The original fraction is = 15/17.
Correct Answer: 60
Explanation:
We have : x + (x% of 150 )= 150
=> x+(x/100)*150] = 150
=>
=> x = (150*2)/5 = 60
Correct Answer: 1060
Explanation:
Total number of sweets
= 80 x 15 x 80/100 + 5 x 80 x 25/100
= 960 + 100 = 1060
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