x = 80 % of y
=> x =(80/100 )y
=> y/x = 5/4
Required percentage = [(y/2x)*100] % = (5/8*100) % =62.5%
Actual price = Rs. (25 + 2.50) = Rs. 27.50.
Saving = 2.50
Percentage Saving = [(2.50/27.50)*100]
= 2500/275
= %
%
Total number of students = 1100 + 700 = 1800.
Number of students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.
Number of failues = 1800-672 = 1128.
Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %.
Let original consumption = 100 kg and new consumption = x kg,
So, 100 * 6 = x * 7.50 => x = 80kg
Reduction in consumption = 20%.
Pass percentage =[(252/270)*100] % =280/3 % = 9 %
Let the total original sale be Rs. 100. Then, original number of visitors = 100.
New number of visitors = 120/0.75 = 160.
Increase % = 60 %.
Present population = 160000 * (1 + 3/100)(1 + 5/200)(1 + 5/100)= 177366.
Population afer 3 years = 64000 * (1 + 5/(2 *100) )^3 = (64000 * 41/40 * 41/40 * 41/40 ) = 68921..
Given 15% of x = 20% of y
=> 15x = 20y
=> x/y = 20/15
=> x : y = 4 : 3
Number of males = 60% of 1000 = 600. Number of females = (1000 - 600) = 400.
Number of literates = 25% of 1000 = 250.
Number of literate males = 20% of 600 = 120.
Number of literate females = (250 - 120) = 130.
Required pecentage = (130/400 * 100 ) % = 32.5 %.
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