Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6)
= 7 : 9 : 3
Given Rushi's one year profit = Rs. 5600
=> Let the total profit = Rs. P
Then,
P x 7/19 = 5600
Total profit P = 19 x 5600/7 = Rs. 15,200.
(b) log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3
∴ log (2 + 3) ≠ log (2 x 3)
(c) Since loga 1 = 0, so log10 1 = 0.
(d) log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3.
So, (b) is incorrect.
Total weight of 2 men
= 1 x 10 + (42 + 38) = 10 + 80 = 90 kg
? Average weight of 2 men = 90/2 = 45 kg
Part filled by A in 1 h = 1/18
Part filled by B in by 1 h = 1/6
Part filled (A + B) in 1 h =1/18 + 1/6 = (1 + 3)/18 = 4/18 = 2/9
Hence, both the pipes together will fill the tank in 9/2 h or 41/2 h
12(1 - t/25) = 3
? t = 45/4 = 111/4 minutes
? Required answer = 111/4 - 3
= 81/4 minutes
Let the extra money invested = ? P
According to the question .
(3000 x 5 x 1)/100 + (P x 8 x 1)/100 = [(3000 + P) x 6 x 1)]/100
? 15000 + 8P = 18000 + 6P
? 2P = 18000 - 15000
? P = 3000/2 = ? 1500
Let the sum of money be Rs y
So Amount = y +[( y x 5 x 4 )/100]
But Amount = Rs 900
? 900 = y +(20y)/100
? 900 = 6y / 5
? y = ( 900 x 5) /6
= Rs 750
Let C.P. of 1 liter milk be Re. 1, Gain = 16 2/3 % = 50/3 %
and S.P. of 1 liter mixture = Re. 1
then C.P. of 1 liter mixture = (1 x (100 x 3) / 350) = Re. (6 / 7)
By the rule of alligation,
Hence, required ratio = (1/ 7) : (6 / 7) = 1 : 6
Total number of words = 5! = 120
combining the vowels at one place(OEA) with remaining 2 letters MG, letters can be arranged in 3! ways. Also, three vowels can be arranged in 3! ways
So, when vowels are together, then number of words = 3! x 3! = 36
there4; Required number of ways, when vowels being never together =120 - 36 = 84
Cost of 1 kg pulses of 1st kind Cost of 1 kg pulses of 2nd kind | ||
Rs. 15 | Mean Price Rs. 16.50 |
Rs. 20 |
3.50 | 1.50 |
∴ Required rate = 3.50 : 1.50 = 7 : 3.
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