Sum of Interior angle is 180 .
and it is given that interior angle is 150 more than exterior,
so let exterior angle is x then interior will be x+150
now , interior + exterior =180
x+150+x=180
x=15
now , number of sides of polygon = 360 / exterior angle
n = 360 / 15
n = 24
Assume that the number is taken as XYZ.
Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9
Condition 2 => Y = X + Z
X Y Z
1 2 1
4 6 2
9 12 3 => (wrong because it is 4 digit.)
and 121 is not divisible by 2
The answer is 462.
From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ?
Now arranging the given numbers in descending order.
837 746 519 495 328
519 - 746/2 = 519 - 373 = 146.
Intial contribution = L/K
After 3 men drop, then contribution =L/K-3
The amount more to pay in contribution =
=
Given exp . is like this
so ans = 854 - 276 = 578
You can find the integers which when divided by 5 have a remainder 2 by adding 2 to all multiples of 5. So we have n = 7 , 12, 17, 22 etc.
From this series we can see that n does not have to be odd.
Also n + 1 can be a prime because, for example, 12 + 1 = 13
And (n + 2) / 7 has a remainder 2 in some cases but not all.
Remember the question asks us for what MUST be true, and we see that none of the statements are true in all cases. However, adding 3 to any of the values of n will always give a multiple of 5.
In case (A), x and y could, for example, both be equal fractions and x/y would be an integer.
4, 14, 24, 34, 44, 54, 64, 74, 84, 94 => has 11 number of (4's)
40, 41, 42, 43, 45, 46, 47, 48, 49 => has 9 number of (4's)
So, totally (11 + 9 = 20) number of 4's in 1 to 100.
If fares for cities L and M from K are x and y respectively, then
2x + 3y = 77 or 6x + 9y = 231...(1)
3x + 2y = 73 or 6x + 4y = 146...(2)
subtracting 2 from 1, we get
5y = 85
y = Rs. 17 => x = Rs. 13
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