Let,
no. of rice bowl = x
no. of dal bowl = y
no. of meat bowl = z
Then, x + y + z = 65 ....(1)
Also given that, 2x = 3y = 4z
substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),
We get x = 30.
As 1 rice bowl is shared between 2 guests,
Therefore, there are 60 guests.
22020 ÷ 0.011 = 2001818.181 ? 2000000
In 12 h, they are at a right angles, 22 times.
So, in 24 h, they are at right angles, 44 times.
P.W. = | 100 x T.D. | = | 100 x 168 | = 600. |
R x T | 14 x 2 |
∴ Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Each number is double the preceding one plus 1. So, the next number is (255 x 2) + 1 = 511.
Here, n(5) = {a, e, i,o, u}
and E = Event of selecting the vowel i = {i}
? P(E)= n(E)/n(S) = 1/5
? 90A/100 = 30B/100 = (30/100) x AC/100
? C = 100 x (100/30) x (90/100) = 300
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