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- Question
The value of log3437 is :
Options- A. 1/3
- B. -3
- C. -1/3
- D. 3
- Correct Answer
- 1/3
Explanation - 1. If a, b, c be the pth, qth and rth terms of a GP then the value of (q-r) log a + (r-p) log b + (p-q) log c is :
Options- A. 0
- B. 1
- C. -1
- D. pqr Discuss
- 2. The number of solutions of the equation logx2x2+40log4xx-14log16xx3=0 is:
Options- A. 0
- B. 1
- C. 2
- D. 3 Discuss
- 3. If a = bx, b = cy and c = az then the value of xyz is equal to :
Options- A. -1
- B. 0
- C. 1
- D. abc Discuss
- 4. The value of log2log5625 is :
Options- A. 2
- B. 5
- C. 10
- D. 15 Discuss
- 5. The value of x satisfying the following relation: log12x = log23x-2
Options- A. 1/3
- B. -1/3
- C. 3
- D. None of these Discuss
- 6. The greatest possible value of n could be 9n < 108 if, given that log 3 = 0.4771 and n?N :
Options- A. 7
- B. 8
- C. 9
- D. 10 Discuss
- 7. If 5x - 17 = -x + 7, then x = ?
Options- A. 4
- B. 5
- C. 7
- D. 9 Discuss
- 8. If A = log321875 and B = log2432187 , then which one of the following is correct?
Options- A. A
- B. A=B
- C. A>B
- D. can't be determined Discuss
- 9. What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?
Options- A. 23
- B. 31
- C. 29
- D. 37 Discuss
- 10. The sum of all two digit numbers divisible by 5 is
Options- A. 945
- B. 678
- C. 439
- D. 568 Discuss
Logarithm problems
Search Results
Correct Answer: 0
Explanation:
Correct Answer: 3
Correct Answer: 1
Correct Answer: 2
Correct Answer: None of these
Explanation:
But at x=-1/3, log x is not defined.
The only admissible value of x is 1.
Correct Answer: 8
Explanation:
Taking Log to both sides
we get
n = 8
Correct Answer: 4
Explanation:
Given equation 5x-17 = -x+7
Add 1x to each side of the equation
5x-17+x = -x+7+x
6x=24
x=4
Correct Answer: A=B
Explanation:
Given
=> A
Therefore, A = B
Correct Answer: 29
Explanation:
87)13601(156
87
-----
490
435
-----
551
522
-----
29
-----
Required number is 29.
Correct Answer: 945
Explanation:
Required numbers are 10,15,20,25,...,95
This is an A.P. in which a=10,d=5 and l=95.
Let the number of terms in it be n.Then t=95
So a+(n-1)d=95.
10+(n-1)*5=95,then n=18.
Required sum=n/2(a+l)=18/2(10+95)=945.
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