If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 1 2 4 8 Given a 2 + b 2 = c 2 Now 1

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Question
If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ?
Options
A. 1
B. 2
C. 4
D. 8

Correct Answer

2

Explanation

Given $a^{2} + b^{2} = c^{2}$

Now $\frac{1}{\log_{c + a} (b)} + \frac{1}{\log_{c - a} (b)}$

= $\log_{b} (c + a) + \log_{b} (c - a)$

= $\log_{b} (c^{2} - a^{2})$

= $2 \log_{b} (b) = 2$

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