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- Question
The value of 13log10125 - 2log104 + log1032 :
Options- A. 0
- B. 1
- C. 2
- D. 4/5
- Correct Answer
- 1
- 1. The sum of the length, breadth and depth of a cuboid is 19 cm and its diagonal is 5? 5 cm, its surface area is?
Options- A. 361 cm2
- B. 125 cm2
- C. 236 cm2
- D. None of these Discuss
- 2. The radius of the base of a right circular cone is doubled. To keep the volume fixed, the height of the come will be?
Options- A. half of the previous height
- B. one-third of the previous height
- C. one-fourth of the previous height
- D. 1/?2 times of the previous height Discuss
- 3. In a survey of a town, it was found that 65% of the people surveyed watch the news on T.V. 40% read a newspaper and 25% read a newspaper and watch the news on T.V. What per cent of the people surveyed neither watch the news on T.V. nor read a newspaper?
Options- A. 5%
- B. 10%
- C. 20%
- D. 15% Discuss
- 4. 6 men can do a piece of work in 12 days while 8 women can do the same work in 18 days. The same work can be done by 18 children in 10 days. 4 men 12 women and 20 children work together for 2 days. If only men have to complete remaining work in 1 day, then find the required number of men.
Options- A. 36
- B. 24
- C. 18
- D. couldn't be determind Discuss
- 5. Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is
Options- A. 25
- B. 10
- C. 15
- D. 20 Discuss
- 6. The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture?
Options- A. 3:2
- B. 4:3
- C. 2:3
- D. 3:4 Discuss
- 7. From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is:
Options- A. 15
- B. 16
- C. 25
- D. 31 Discuss
- 8. A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
Options- A. 58 l
- B. 65 l
- C. 50 l
- D. 62 l Discuss
- 9. 4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:
Options- A. 49 : 221
- B. 39:231
- C. 94:181
- D. None of these Discuss
- 10. A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, the profit %?
Options- A. 22.5%
- B. 25%
- C. 20%
- D. 33.33% Discuss
More questions
Correct Answer: 236 cm2
Explanation:
Let x, y and z be the length breadth and deapth of a cuboid.
? x + y + z = 19
x2 + y2 + z2 = (5?5)2 = 125
Surface area of the cuboid = 2(xy + yz + zx)
= (x + y + z)2) - (x2 + y2 + z2)
= 361 - 125 = 236 cm3
Correct Answer: one-fourth of the previous height
Explanation:
In first situation.
Radius = r1, height = h1 and volume = v1
In second situation,
Radius =2r1, height = h2 and volume = v2
In the volume is fixed, then
v1 = v2
? (1/3)?r21h1 = (1/3)?(2r1)2h2
? h1 = 4h2
? h2 = h1/4
Therefore, height of the the cone will be one-fourth of the previous height.
Correct Answer: 20%
Explanation:
Required percentage
= 100 ? (40 + 25 + 15)
= 100 ? 80 = 20%
Correct Answer: 36
Explanation:
6 x 12 men = 8 x 18 women = 18 x 10 children
? 12 men = 24 women = 30 children
? 2 men = 4 women = 5 children
Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men
Time to do remaining work in 1 man = (6 x 12 - 18 x 2) = 36 days
? Required number of men to finish the work in 1 days = 36
Correct Answer: 20
Explanation:
Solution 1.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = 30 - X ;
According to the question,
3X - (30 - X) x 2 = 40
? 3x - 60 + 2x = 40
? 5x - 60 = 40
? 5x = 40 + 60 ? x = 100/5 = 20
? Mohan attempted 20 questions correctly .
Solution 2.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = Y ;
According to given question;
X + Y = 30 ; -----------i
3X - 2Y = 40 ;-------ii
Now multiply the first equation by 2;
we will get
2X + 2Y = 60 ;--------iii
After Add the equation ii and iii , we will get
3X - 2Y + 2X + 2Y = 40 + 60 ;
? 5X = 100 ;
? X = 20;
? Mohan attempted 20 questions correctly .
Correct Answer: 3:2
Explanation:
Concentration of glucose are in the ratio =
Quantity of glucose taken from A = 1 liter out of 2
Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit
Quantity of glucose taken from C = 0.8 lit
So, total quantity of glucose taken from A,B and C = 3.6 lit
So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit
Ratio of glucose to alcohol = 3.6/2.4 = 3:2
Correct Answer: 15
Explanation:
Let quantity of mixture be x liters.
Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid = units, Where n = no of operations .
So, Quantity of Milk =
Given that, Milk : Water = 9 : 16
=> Milk : (Milk + Water) = 9 : (9+16)
=> Milk : Mixture = 9 : 25
Therefore,
=> x = 15 liters
Correct Answer: 50 l
Explanation:
Let the tin contain 5x litres of liquids
=> 5(4x - 36) = 2(x + 36)
=> 20x - 180 = 2x + 72
=> x = 14 litres
Hence, the initial quantity of mixture = 70l
Quantity of liquid B
=
= 50 litres.
Correct Answer: 49 : 221
Explanation:
Copper in 4 kg = 4/5 kg and Zinc in 4 kg = 4 x (4/5) kg
Copper in 5 kg = 5/6 kg and Zinc in 5 kg = 5 x (5/6) kg
Therefore, Copper in mixture = kg
and Zinc in the mixture = kg
Therefore the required ratio = 49 : 221
Correct Answer: 25%
Explanation:
As water costs free, water sold at cost price of milk gives the profit.
Required profit % = 5/20 x 100 = 5 x 5 = 25%.
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