= log 1 + log 1 +.....+log 1
= 0.
=
log (0.0000134). Since there are four zeros between the decimal point and
the first significant digit, the characteristic is ?5.
5x+1=2x+10
3x=9
x=3
for (k,l) > 0 and k > l
Let k = x+1 and l = x
Therefore,
(x + 1) > x
Therefore,
Rewrite equation as
Leads to 2x + 1 = 0
Solve for x : x = -1/2
Given
Now
=
=
=
log (2 + 3) = log 5
log (2 x 3) = log 2 + log 3
log (2 + 3)
log (2 x 3)
By trial and error method, when we substitute
x = 0
Both LHS and RHS are equal.
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