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  • Question
  • For x?N, x>1 , and p=logxx+1 , q=logx+1x+2 then which one of the following is correct?


  • Options
  • A. p < q
  • B. p = q
  • C. p > q
  • D. can't be determined

  • Correct Answer
  • p > q 

    Explanation

    k l > k + 1 l + 1  for (k,l) > 0 and  k > l 

     

     

     

    Let     k = x+1    and   l = x

     

     

     

    Therefore,  x + 1 x > ( x + 1 ) + 1 ( x ) + 1

     

     

     

     (x + 1) > x

     

     

     

    Therefore,  log ( x + 1 ) log ( x ) > log ( x + 2 ) log ( x + 1 )

     

     

     

    ? log x x + 1   > log x + 1 x + 2

  • Tags: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO

    Logarithm problems


    Search Results


    • 1. Solve the equation 122x+1 = 1 ?

    • Options
    • A. -1/2
    • B. 1/2
    • C. 1
    • D. -1
    • Discuss
    • 2. The least value of the expression 2log10x - logx1100 for x>1 is:

    • Options
    • A. 2
    • B. 3
    • C. 4
    • D. 5
    • Discuss
    • 3. if logab+logba=loga+b,then

    • Options
    • A. a + b = 1
    • B. a - b = 1
    • C. a = b
    • D. ab=1
    • Discuss
    • 4. What is the number of digits in 333 ? Given that log3 = 0.47712?

    • Options
    • A. 12
    • B. 13
    • C. 14
    • D. 15
    • Discuss
    • 5. If log8x = 313 then find the value of x?

    • Options
    • A. 25
    • B. 32
    • C. 37
    • D. None of these
    • Discuss
    • 6. if log105+log5x+1=log10(x+5)+1,then x is equal to

    • Options
    • A. 1
    • B. 3
    • C. 5
    • D. 10
    • Discuss
    • 7. What is the characteristic of the logarithm of 0.0000134?

    • Options
    • A. 5
    • B. -5
    • C. 6
    • D. -6
    • Discuss
    • 8. Find value of log27 +log 8 +log1000log 120

    • Options
    • A. 1/2
    • B. 3/2
    • C. 2
    • D. 2/3
    • Discuss
    • 9. The Value of logtan10+logtan20+??+logtan890 is

    • Options
    • A. -1
    • B. 0
    • C. 1/2
    • D. 1
    • Discuss
    • 10. The value of 13log10125 - 2log104 + log1032 :

    • Options
    • A. 0
    • B. 1
    • C. 2
    • D. 4/5
    • Discuss


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