=
=
=
=
.
⟹ 2x = 38.
⟹ x = 19.
∴ Son's age 5 years back (19 - 5) = 14 years.
Increase% = (1/8) x 100% = 12.5%
Height after 2 years =64 x {1 +25/(2 x 100)}2
= 64 x 9/8 x 9/8
= 81 cm
Given, P = ? 8000, R = 5% and n = 2 Yr
According to the formula,
Amount = p ( 1 + R / 100 )n
= 8000 ( 1 + 5/100 )2
= 8000 x (105/100)2
=8000 x (21/20) x (21/20)
= 20 x 21 x 21
= ? 8820
4.036 | = | 403.6 | = 100.9 |
0.04 | 4 |
Hint 1.
Let consider the monthly income = x ;
Amount spend on House rent = 2x/5;
Amount spend on food = 3x/10;
Amount spend on conveyance = x/8;
After Expenditure , The left amount = 2800;
According to Question;
x - ( 2x/5 + 3x/10 + x/8 ) = 2800 ;
x- ((16x + 12x + 5x)/40) = 2800 ;
x - 33x/40 = 2800 ;
(40x - 33x)40 = 2800 ;
7x/40 = 2800 ;
7x = 2800 x 40 ;
x = 2800 x 40/7 ;
x = 400 x 40 ;
x = 16000 ;
Expenditure on food = 3x/10 = 3 x 16000 /10= ? 4800
Expenditure on conveyance = x/8 = 1 x 16000/8 = ? 2000
? Expenditure on food and conveyance together
=? (4800 + 2000) = ? 6800
Solution 2 .
part of income left
= 1 - (2/5 + 3/10 + 1/8 )
=1- (16 + 12 + 5/40)
= 1- 33/40 = 40 - 33/40 = 7 /40
Let the monthly income = x
According to the question,
7/40 x = 2800
? x = 2800 x 40/7
= 400 x 40 = ? 16000
Expenditure on food = 3/10 x 16000 = ? 4800
Expenditure on conveyance = 1/8 x 16000 = ? 2000
? Expenditure on food and conveyance together
=? (4800 + 2000) = ? 6800
Let the ten's place digit = x
and unit's place digit = y
? The original number = 10x + y
After interchanging the digits
Number will become 10y + x
? according to the given question,
y + x = 13 and
(10y + x ) - (10x + y) = 27
? 9y - 9x = 27
? y - x = 3 ................(i)
and y + x = 13 .................(ii)
On solving Eqs.(i) and (ii) , we get
y = 8 and x = 5
? Required number is
10x + y = 10 x 5 + 8 = 58
So, the correct next number is 1440.
1 |
8 |
Then, 2n = 16 = 24 ⟹ n = 4.
∴ log2 16 = 4.
Work done by X in 4 days = | ❨ | 1 | x 4 | ❩ | = | 1 | . |
20 | 5 |
Remaining work = | ❨ | 1 - | 1 | ❩ | = | 4 | . |
5 | 5 |
(X + Y)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 8 | = | 2 | . |
20 | 12 | 60 | 15 |
Now, | 2 | work is done by X and Y in 1 day. |
15 |
So, | 4 | work will be done by X and Y in | ❨ | 15 | x | 4 | ❩ | = 6 days. |
5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
Given, T1 = 21/2 yr, T2 = 4 Yr
According to the question.
[P + (P x R x 4)/100] - [P + (P x R x 2.5)/100] = 1067.20 - 1012 = 55.2
? (1.5 x P x R)/100 = 55.2
? PR = (552 x 100) / 15 = 3680
For 4 yr.
SI = PRT/100 = (3680 x 4)/100 = ? 147.2
? Sum (P) = 1067.2 - 147.2 = ? 920
We have, PR = 3680
? R = 3680/P = 3680/920 = 4%
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