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- Question
A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?
Options- A. Data inadequate
- B. 8 units
- C. 12 units
- D. None of these
- Correct Answer
- Data inadequate
- 1. An observer 1.6 m tall is 20 3 away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:
Options- A. 21.6 m
- B. 23.2 m
- C. 24.72 m
- D. None of these Discuss
- 2. If an object travels at five feet per second, how many feet does it travel in one hour?
Options- A. 30
- B. 3000
- C. 18
- D. 1800 Discuss
- 3. Three friends J, K and L jog around a circular stadium and complete one round in 12, 18 and 20 seconds respectively. In how many minutes will all the three meet again at the starting point.
Options- A. 5
- B. 8
- C. 12
- D. 3 Discuss
- 4. What is the LCM of 120 and 450?
Options- A. 2400
- B. 1800
- C. 3600
- D. 4800 Discuss
- 5. What is the HCF (highest common factor) of 133 and 112?
Options- A. 15
- B. 7
- C. 19
- D. 6 Discuss
- 6. A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ?
Options- A. 1080 cm
- B. 180 m
- C. 108 m
- D. 118 cm Discuss
- 7. Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Options- A. 173 m
- B. 200 m
- C. 273 m
- D. 300 m Discuss
- 8. Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?
Options- A. 6
- B. 8
- C. 9
- D. 10 Discuss
- 9. The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ?
Options- A. 42.2 mts
- B. 33.45 mts
- C. 66.6 mts
- D. 58.78 mts Discuss
- 10. A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? ?
Options- A. 14 cm
- B. 13.5 cm
- C. 12.5 cm
- D. 11.4 cm Discuss
Height and Distance problems
Search Results
Correct Answer: 21.6 m
Correct Answer: 1800
Correct Answer: 3
Explanation:
All the three friends will meet at the starting point again after X seconds, such that X is the LCM of the times taken by J, K and L to complete one round.
=> LCM of 12, 18 and 20 = 180 seconds = 3 minutes.
Hence 3 minutes is the answer.
Correct Answer: 1800
Correct Answer: 7
Correct Answer: 108 m
Explanation:
We know the rule that,
At particular time for all object , ratio of height and shadow are same.
Let the height of the pole be 'H'
Then
=> H = 108 m.
Correct Answer: 273 m
Correct Answer: 8
Explanation:
Average speed = total distance / total time
Total distance covered = 6 miles; total time = 45 minutes = 0.75 hours
Average speed = 6/ 0.75 = 8 miles/hour
Correct Answer: 66.6 mts
Correct Answer: 12.5 cm
Explanation:
Let the required height of the building be x meter
More shadow length, More height(direct proportion)
Hence we can write as
(shadow length) 40.25 : 28.75 :: 17.5 : x
? 40.25 × x = 28.75 × 17.5
? x = 28.75 × 17.5/40.25
= 2875 × 175/40250
= 2875 × 7/1610
= 2875/230
= 575/46
= 12.5 cm
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