Suppose commodity X wil cost 40 paise more than Y after Z years. Then,
(4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40
=> 0.25Z = 0.40 + 2.10 => Z= 2.50/0.25 = 10
Therefore, X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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