S=R[(1+i)^n-1)/i]
Amount = Rs. (30000 + 4347) = Rs. 34347
(1+7/100)^n=34347
Let the sum be Rs. x. Then
C.I=x[1+4/100)^2-x]=[626/675x-x]
S.I=x^2/25
C.I-S.I=1
S=R[(1+i)^n-1]/i
M=P(1+i)^n
M = p(1+i)^n
S=R[(1+i)^n-1)/i]
A=R[(1+i)^n-1]/i(1+i)^n
A=R[(1+i)^n-1]/i(1+i)^n
R=S[i/(1+i)^n-1]
R=S[i/(1+i)^n-1]
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