E=e^i-1
E=(1+i/n)^n-1
l=(F/P)^1/n-1
A=P(1+r)^t
I=Prt
I=12
Balance = P +Prt
412
Find the balance at the end of the second year.
I = Prt=12.36
Balance =P + Prt
424.36
A = P + Prt
The only part of this type of calculation that needs particular
care is that concerning the interest rate. The formula assumes that
r is a proportion, and so, in this case:
r = 0.08
In addition, we have P = 5,000 and n = 5, so:
V = P(1 + r)5 = 5,000 x (1 + 0.08)5 = 5,000 x 1.469328 = 7,346.64
Thus the value of the investment will be 7,346.64
M = p(1+i)^n
M=P(1+i)^n
S=R[(1+i)^n-1]/i
Let the sum be Rs. x. Then
C.I=x[1+4/100)^2-x]=[626/675x-x]
S.I=x^2/25
C.I-S.I=1
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