A=P(1+r)^t
I=Prt
I=12
Balance = P +Prt
412
Find the balance at the end of the second year.
I = Prt=12.36
Balance =P + Prt
424.36
A = P + Prt
FV=P(1+r/n)^nt
FV=P(1+r/n)^nt
Given: T = 3 years.
I. gives: R = 8% p.a.
II. gives: S.I. = Rs. 1200.
Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.
Difference between C.I. and S.I. may be obtained.
So, the correct answer is (D).
l=(F/P)^1/n-1
E=(1+i/n)^n-1
E=e^i-1
The only part of this type of calculation that needs particular
care is that concerning the interest rate. The formula assumes that
r is a proportion, and so, in this case:
r = 0.08
In addition, we have P = 5,000 and n = 5, so:
V = P(1 + r)5 = 5,000 x (1 + 0.08)5 = 5,000 x 1.469328 = 7,346.64
Thus the value of the investment will be 7,346.64
M = p(1+i)^n
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