A = P + Prt
FV=P(1+r/n)^nt
FV=P(1+r/n)^nt
Given: T = 3 years.
I. gives: R = 8% p.a.
II. gives: S.I. = Rs. 1200.
Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.
Difference between C.I. and S.I. may be obtained.
So, the correct answer is (D).
[15000*(1+r/100)2-15000]-(15000*r*2)/100=96
Rate=8%
S.I. = Rs.(1200*10*1)/100=rs.120
C.I. =rs[1200*(1+5/100)2-1200]=rs.123
Difference = Rs.(123-120) =Rs.3
I=Prt
I=12
Balance = P +Prt
412
Find the balance at the end of the second year.
I = Prt=12.36
Balance =P + Prt
424.36
A=P(1+r)^t
l=(F/P)^1/n-1
E=(1+i/n)^n-1
E=e^i-1
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