Given: T = 3 years.
I. gives: R = 8% p.a.
II. gives: S.I. = Rs. 1200.
Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.
Difference between C.I. and S.I. may be obtained.
So, the correct answer is (D).
[15000*(1+r/100)2-15000]-(15000*r*2)/100=96
Rate=8%
S.I. = Rs.(1200*10*1)/100=rs.120
C.I. =rs[1200*(1+5/100)2-1200]=rs.123
Difference = Rs.(123-120) =Rs.3
Sum = Rs.(50*100)/2*5=Rs.500
Amount=Rs.[500*(1+5/100)2]
= Rs. 551.25
C.I = Rs.(551.25-500)= Rs.51.25
Let Principal = Rs. P and Rate = R% p.a. Then,
Amount=
C.I =
Clearly, it does not give the answer
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000*(1+7/100)^n=34347
n= 2 years
FV=P(1+r/n)^nt
FV=P(1+r/n)^nt
A = P + Prt
I=Prt
I=12
Balance = P +Prt
412
Find the balance at the end of the second year.
I = Prt=12.36
Balance =P + Prt
424.36
A=P(1+r)^t
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.